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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
Thank you so much Agdimple,

It was corrected.

Steve.
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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
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I am getting D.

Equation is \((x+2) \sqrt{x-x^2}=0\)
x+2=0 or x=-2
\(\sqrt{x-x^2}=0\)
x-x^2=0
x(1-x)=0
or x=0
or x=1

Average of all roots= -2+0+1/3=-1/3.
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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
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the solutions are x = -2,0 and 1
the mean = -1/3.
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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
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Excellent Official Questions.
Here is my solution to this one =>
The roots of the equation will be => {-2,0,1}

Hence the mean => \(\frac{-2+0+1}{3} => \frac{-1}{3}\)
Hence D
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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
Just to know, is there a possibility o create an eq multiplying both terms?
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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
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SteveNew wrote:
Find the arithmetic mean of all roots of the following equation

\((x+2) \sqrt{x-x^2}=0\)

A) 2
B) 1
C) 0.5
D) -1/3
E) 0.3


Why is -2 considered a solution? the square root of a negative number doesn't exist, if you plugg in back in the equation this is impossible...
Hence, only possible solutions are 0 and 1; so C

Can someone help?
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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
app219 wrote:
SteveNew wrote:
Find the arithmetic mean of all roots of the following equation

\((x+2) \sqrt{x-x^2}=0\)

A) 2
B) 1
C) 0.5
D) -1/3
E) 0.3


Why is -2 considered a solution? the square root of a negative number doesn't exist, if you plugg in back in the equation this is impossible...
Hence, only possible solutions are 0 and 1; so C

Can someone help?


+1

Can someone please explain why -2 is a valid root of this equation in-spite of having a negative square root in the expression?
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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
-2, 0,1 are roots (-2 is root because 0 * imaginary no. is 0) average=-1/3

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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
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Whenever any such equation is given one must put the critical points in each other to see if any rule is not broken. If oneself is doubtful then best way is to back process the whole.
Square root of {(x+2)(x-x^2)} = 0
Square root of {x^3 - x^4 +4x -4x^2} = 0
Square root of {x^3(1-x) +4x(1-x)} = 0
Square root of {(x^3+4x)(1-x)} = 0
so;
(x^3+4x)(1-x)>=0
x(x^2+4)(1-x)=0 to find the critical points
x=0 or x=1 or
x^2=-4 this is not possible

so roots are 0 and 1
ans is 0.5
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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
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Re: Find the arithmetic mean of all roots of the following equation [#permalink]
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