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CEO
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As part of a game, four people each must secretly choose an [#permalink]
23 Sep 2003, 14:54
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As part of a game, four people each must secretly choose an integer between 1 and 4, inclusive. What is the approximate likelihood that all four people will choose different numbers?
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Total choices possible = 4^4.
All 4 select different number = 4!
Hence, likelihood of all 4 selecting different nos. = 4!/4^4
= 3/32.
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