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Company A imported 10,500 widgets made of either brass or aluminum.

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Bunuel
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Company A imported 10,500 widgets made of either brass or aluminum. [#permalink] New post   05 Jan 2015, 07:03
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Tough and Tricky questions: Word Problems.



Company A imported 10,500 widgets made of either brass or aluminum. The widgets are painted blue, red or green. If 10 percent of the widgets are made of brass and of those 20 percent are painted green and 40 percent are painted red how many brass widgets painted blue were imported?

A. 420
B. 840
C. 1050
D. 1680
E. 2100

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Re: Company A imported 10,500 widgets made of either brass or aluminum. [#permalink] New post   05 Jan 2015, 07:31
Answer A.

We are told that 10% of all imported widgets are made of brass and of those, 20% are green and 40% are red. Since we know that there are only three colors, the remaining 40% must be blue. 40% blue of 10% brass widgets leads to 4% blue brass widgets out of the total 10,550 widgets.

10,500 /100 * 4 = 420. Answer A.
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Re: Company A imported 10,500 widgets made of either brass or aluminum. [#permalink] New post   05 Jan 2015, 17:42
Bunuel wrote:

Tough and Tricky questions: Word Problems.



Company A imported 10,500 widgets made of either brass or aluminum. The widgets are painted blue, red or green. If 10 percent of the widgets are made of brass and of those 20 percent are painted green and 40 percent are painted red how many brass widgets painted blue were imported?

A. 420
B. 840
C. 1050
D. 1680
E. 2100

Kudos for a correct solution.



brass widgets B = 10500 * 10/100 = 1050
Brass widgets painted blue = 100 - 20- 40 = 40%

i.e 40% of 1050 = 420

Ans A
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Re: Company A imported 10,500 widgets made of either brass or aluminum. [#permalink] New post   05 Jan 2015, 19:19
Answer = A. 420

Brass widgets \(= \frac{10}{100} * 10500 = 1050\)

Of these, 20% green & 40% red.

Remaining blue \(= 100-(20+40) = \frac{40}{100} * 1050 = 420\)
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Re: Company A imported 10,500 widgets made of either brass or aluminum. [#permalink] New post   05 Jan 2015, 20:50
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Answer A: 420.

Since 10% are made of brass - 1050.
Of these 20% are green and 40% are red. So 40% are blue.

So blue brass = 40% of 1050 = 40*1050/100 = 420.


Bunuel wrote:

Tough and Tricky questions: Word Problems.



Company A imported 10,500 widgets made of either brass or aluminum. The widgets are painted blue, red or green. If 10 percent of the widgets are made of brass and of those 20 percent are painted green and 40 percent are painted red how many brass widgets painted blue were imported?

A. 420
B. 840
C. 1050
D. 1680
E. 2100

Kudos for a correct solution.
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Bunuel
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Re: Company A imported 10,500 widgets made of either brass or aluminum. [#permalink] New post   08 Jan 2015, 09:53
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Bunuel wrote:

Tough and Tricky questions: Word Problems.



Company A imported 10,500 widgets made of either brass or aluminum. The widgets are painted blue, red or green. If 10 percent of the widgets are made of brass and of those 20 percent are painted green and 40 percent are painted red how many brass widgets painted blue were imported?

A. 420
B. 840
C. 1050
D. 1680
E. 2100

Kudos for a correct solution.


OFFICIAL SOLUTION:

(A) Question asks for the number of brass widgets painted blue.

First, determine the number of widgets that are brass:
(0.1)(10,500) = 1,050

Next, determine the percentage of brass widgets that are painted blue: 100% – 20% green – 40% red = 40% blue

Finally, determine the number of brass widgets painted blue: (0.4)(1,050) = 420
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Re: Company A imported 10,500 widgets made of either brass or aluminum. [#permalink] New post   04 Dec 2019, 01:33
Given : 10% of the Widgets are made of Brass of those 20% are colored green and another 40% are colored red


100 - 20 - 40 = 40%

40 % of 10% of 10500 = required


\(\frac{40}{100} * \frac{10}{100} * 10500\)

4 * 105 = 420
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Re: Company A imported 10,500 widgets made of either brass or aluminum. [#permalink]
04 Dec 2019, 01:33
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