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Answer = A. 420

Brass widgets \(= \frac{10}{100} * 10500 = 1050\)

Of these, 20% green & 40% red.

Remaining blue \(= 100-(20+40) = \frac{40}{100} * 1050 = 420\)
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Answer A: 420.

Since 10% are made of brass - 1050.
Of these 20% are green and 40% are red. So 40% are blue.

So blue brass = 40% of 1050 = 40*1050/100 = 420.


Bunuel

Tough and Tricky questions: Word Problems.



Company A imported 10,500 widgets made of either brass or aluminum. The widgets are painted blue, red or green. If 10 percent of the widgets are made of brass and of those 20 percent are painted green and 40 percent are painted red how many brass widgets painted blue were imported?

A. 420
B. 840
C. 1050
D. 1680
E. 2100

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Bunuel

Tough and Tricky questions: Word Problems.



Company A imported 10,500 widgets made of either brass or aluminum. The widgets are painted blue, red or green. If 10 percent of the widgets are made of brass and of those 20 percent are painted green and 40 percent are painted red how many brass widgets painted blue were imported?

A. 420
B. 840
C. 1050
D. 1680
E. 2100

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OFFICIAL SOLUTION:

(A) Question asks for the number of brass widgets painted blue.

First, determine the number of widgets that are brass:
(0.1)(10,500) = 1,050

Next, determine the percentage of brass widgets that are painted blue: 100% – 20% green – 40% red = 40% blue

Finally, determine the number of brass widgets painted blue: (0.4)(1,050) = 420
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Given : 10% of the Widgets are made of Brass of those 20% are colored green and another 40% are colored red


100 - 20 - 40 = 40%

40 % of 10% of 10500 = required


\(\frac{40}{100} * \frac{10}{100} * 10500\)

4 * 105 = 420
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