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\(F-10=S+10\) \(2*(S-20)=F+20\) \(2S-40=F+20\) \(2S-F=60\) do some annoying math
Based on the fact that you can move passangers and get a 2/1 split, this means the total number of passengers must be divisible by 3. You can also eyeball the numbers and realize 300 or 600 will be too big. This means it should be 180. Plug it in logically and you must have 80 and 100 to satisfy equation 1, and the same split works for equation 2.
Algebra always works but you can always use concepts if algebra isn't your strong suit.
Re: A child on a controlled diet is fed 300 ounce of a mixture [#permalink]
19 Apr 2013, 12:54
A child on a controlled diet is fed 300 ounce of a mixture of two foods a and b food a contains 10% protein and food b contains 15% protein if child diet contains exactly 38 ounce of protein daily. How many ounce of food a are in the mixture?
a.100 b.140 c.150 d.160 e.200
Oh, just to show how I got it (a little different from above)
A is 10% protein and B is 15%.
I just ran through the answers quickly.
A - If 100 oz of food A, thats 10 oz of protein. Which leaves 200 oz of food B and 30 oz protein, too much. B - If 140 oz of food A, thats 14 oz of protein. 160 oz of food B is 16+8 (10%+5%) and we're at 38!
It was relatively easy to run through these so you could probably start from anywhere and work your way around but I solved this in less than a minute this way.
"You may not realize it when it happens, but a kick in the teeth may be the best thing in the world for you." - Walt Disney
Re: .A train covered a certain distance at uniform speed [#permalink]
19 Apr 2013, 13:50
11.A train covered a certain distance at uniform speed if train would have been 6miles/hour faster it would have taken 4 hrs less than the scheduled time and if the train were slower by 6 miles/hour it would have taken 6 hrs more than the scheduled time find the distance in miles of journey a.840 b.780 c.720 d.680 e.630
3 situations are give. Distance is same in all 3.
Situation 1 Let 'S', 'T' & 'D' are the standard Speed, time & distance of the train.
Re: the charges for a 5 day trip by tourisim bus for one full an [#permalink]
19 Apr 2013, 19:36
6.the charges for a 5 day trip by tourisim bus for one full and half ticket is 1440 iccluding of boarding charges which are same for a full as well as a half ticket the charges for the same trip for 2 full and one half ticket the charges are 2220the fare for half ticket is 75% of the full ticket find the difference betwn the fare and boarding charges for one full ticket a.480 b.360 c.300 d.240 e.180
Ok. So variables are Fare and Boarding. Charges for full is 4x and half is 3x. Now,
(4x+3x) + 2 Boarding = 1440 7x+2B= 1440 Similary, (4x*2+3x) + 3B = 2220 11x+3B = 2220 Solve for X and B, we need to find 4X - B = 180
Re: Albert invested a some amount at rate of 3% per quaterly sim [#permalink]
19 Apr 2013, 19:46
Albert invested a some amount at rate of 3% per quaterly simple interest and other amount at the rate of 7.5% half yearly simple interest. he received 1500$ as interest for a year. if he had interchanged the amount invested he would have received 78$ more as interest for the year. Find the smallest investment
a.7062.5$ b.5762.5$ c.7562.5$ d.5002.0$ e.7002.0$
Ok. It is simple interest. Quarterly 3% is equal to 12 % yearly. Similarly, 7.5% is 15% yearly. Now, let amounts be A and B. Then. 12% A + 15% B = 1500 12% B + 15% A = 1578
Solving for A and B. (A - B)/100 = 78/3 = 26
Now put A = 2600 + B in eq 1 12/100(2600+B) + 15/100 (B) = 1500