For each month of next year, Company R's monthly revenue target is x

Please help me understand how did we calculate x=10,000 from statement 2.

It is an arithmetic progression:

Let R be the revenue target for June.
For July; revenue target=R+x
For August; revenue target=R+2x
For September; revenue target=R+3x

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of mext year.

\(R+3x-R=30000\)
\(x=10000\)-------------------------1
Not Sufficient.

(1) Company R's revenue target for December of next year is $310,000

Let Jan's revenue target be J,

Common difference is "x". First term(January)=J; Last term or 12th term, say D(December)

\(A_n=A_1+(n-1)d\)

\(D=J+(n-1)x\)
\(D=J+(12-1)x\)

\(310000=J+11x\)-----2
Not Sufficient.

Using 1 and 2, we get J and we know x.

March Revenue Target= J+2x
Sufficient.

Ans: "C"

JAN FEB MAR APR MAY......... .DEC
a a+x a+2x a+11x


a+2x=?

1. Not Sufficient
a+11x = 310000

we dont know a or x. In other words different a , will give different x.

2. Not sufficient

a+8x = 30000 + a+5x

x can be found . But no info on a.

Together,

a+11x = 310000 and we have x from 2.

Hence this is Sufficient.

Answer is C.

J (January), J + X, J +2X = ?
1) J + 11X = 310,000 Not sufficient.
2) J + 8X = J + 5X + 30,000 ; 3X = 30,000 ; X = 10,000
But do not know J, not sufficient
1) & 2) J + 11*10,000 = 310,000 ; J = 200,000 Done
Answer C.

Given: Monthly revenue target is x dollars greater than the target for the previous month
Required: Revenue for March of next year

Statement 1: Target for Dec = 310,000
Target for January = 310,000 + x
Target for February = 310,000 + 2x
Target for March = 310,000 = 3x

But we have no clue about x
INSUFFICIENT

Statement 2: Revenue for September - Revenue for June = 30,000
Hence 3x = 30,000
But we have no idea about the actual revenues.
INSUFFICIENT

Combining both statements:
We know the value of x and we know the value in one of the months,
Hence we can calculate the revenue in March
SUFFICIENT

Correct Option: C

Hi , Bunuel, Veritas Karishma request to suggest if following method of solving is accurate. Pls suggest if any shortcut to solve to save time.


( Note: Do not make mistake of assuming Jan's revenue as X)

Soln:
Next year let january revenue be J
Then feb revenue will be J+x ( as given revenue target increases by x to previous months target)
March will be J+ x+x= J+ 2x
April will be J+3x and so on....

St 1 says Dec revenue target is 310,000

Dec target in terms of variables above will be J+11x
so we can say J+11x= 310,000

But we do not know what is value of J nor we know value of x . Without which we cannot further find value of March.
Hence St 1 is not sufficient

St 2 Revenue target for September of next year is $30,000 greater than its revenue target for June of next year.

June's target =J+5x
Sep's target= J+8x

as per st 2 J+8x=J+5x+30000
solving this eq, we get x = 10,000

We want to find March's target = J+2x
we know value of x but dont know value of J so cannot find . Hence st 2 Not sufficient

St1 and St 2 together,

J+11x=310,000 and x = 10,000

We can find value of J now by replacing value of x in J+11x=310,000...hence J=200,000 and x =10000
and also cal March's revenue target using value of J and x . March = 220000

Ans is C

Say,
Target for Jan = J
Target for Feb = J + x
Target for March = J + 2x
...
Target for Dec = J + 11x

We need to find the value of J + 2x.

(1) Company R's revenue target for December of next year is $310,000

J + 11x = 310,000
We don't know J and x. Two variables but only 1 equation. Lots of possibilities.

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year.

Target for June = J + 5x
Target for Sept = J + 8x
3x = 30,000
x = 10,000
We don't know what is J so cannot find J + 2x.

Using both, we know x and plugging x in stmnt 1, we can get value of J. So we can find J + 2x.
Sufficient.

Answer (C)

VeritasKarishma where is it mentioned that revenue was increasing by a constant. it says " R's monthly revenue target is x dollars greater" and as per ST 2
"revenue target for September of next year is $30,000 greater than its revenue target for June of next year" why do you assume that growth of revenue (the value 30K is constant throughout year ?:/ ) it doesnt necessarily mean that each month it was +30K greater than previous one, it could be any number i mean 5k, 10k, 15K 20K etc

You are given that for each month, the target is x more than the preceding month target.

"For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month."

So if target for Jan in J, target for Feb will be J + x (x more than preceding month i.e. Jan target).
If target for Feb is J + x, target for March will be J + x + x (x more than preceding month i.e. Feb target)

and so on...

So let initially for Jan, the rev was a$, and for the next 11 months the revenue increases something like this:
a , a+x, a+2x, a+3x , a+4x........ a+11x (Jan till December)


(1) Company R's revenue target for December of next year is $310,000

a+11x= 310000$ (two unknowns, we can't find anything from this one)

Insufficient.

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year.

sept: a+8x
June= a+5x

as per the second statement, a+8x= 30,000+(a+5x)
x= 10,000

we need march's revenue, which is a+ 2x, we have x from 2, but we still need "a".

Insufficient.

1+2

a+11x= 310000$ , we now have x= 10,000, so we plug that in, we'll get a

once we have a and x both, solving a+2x is as a candy from a kid


C is the answer.

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