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# For each month of next year, Company R's monthly revenue target is x

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Q49  V35
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Re: For each month of next year, Company R's monthly revenue target is x [#permalink]
eschn3am wrote:
Answer is C

1. We know the target for December is $310,000. We know March is 9 months earlier, but we don't know x. 2. We know X is$10,000 but have no starting point to find March with.

combined we know $310,000 is December Nov:$300,000
Oct: $290,000 Sep:$280,000
Aug: $270,000 July:$260,000
June: $250,000 May:$240,000
April: $230,000 March:$220,000

or you could just take $310,000 - ($10,000 * 9 months) = $220,000 Please help me understand how did we calculate x=10,000 from statement 2. Retired Moderator Joined: 20 Dec 2010 Posts: 1107 Own Kudos [?]: 4754 [3] Given Kudos: 376 Re: For each month of next year, Company R's monthly revenue target is x [#permalink] 2 Kudos 1 Bookmarks DeeptiM wrote: eschn3am wrote: Answer is C 1. We know the target for December is$310,000. We know March is 9 months earlier, but we don't know x.

2. We know X is $10,000 but have no starting point to find March with. combined we know$310,000 is December
Nov: $300,000 Oct:$290,000
Sep: $280,000 Aug:$270,000
July: $260,000 June:$250,000
May: $240,000 April:$230,000
March: $220,000 or you could just take$310,000 - ($10,000 * 9 months) =$220,000

Please help me understand how did we calculate x=10,000 from statement 2.

It is an arithmetic progression:

Let R be the revenue target for June.
For July; revenue target=R+x
For August; revenue target=R+2x
For September; revenue target=R+3x

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of mext year. $$R+3x-R=30000$$ $$x=10000$$-------------------------1 Not Sufficient. (1) Company R's revenue target for December of next year is$310,000

Let Jan's revenue target be J,

Common difference is "x". First term(January)=J; Last term or 12th term, say D(December)

$$A_n=A_1+(n-1)d$$

$$D=J+(n-1)x$$
$$D=J+(12-1)x$$

$$310000=J+11x$$-----2
Not Sufficient.

Using 1 and 2, we get J and we know x.

March Revenue Target= J+2x
Sufficient.

Ans: "C"
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Re: For each month of next year, Company R's monthly revenue target is x [#permalink]
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JAN FEB MAR APR MAY......... .DEC
a a+x a+2x a+11x

a+2x=?

1. Not Sufficient
a+11x = 310000

we dont know a or x. In other words different a , will give different x.

2. Not sufficient

a+8x = 30000 + a+5x

x can be found . But no info on a.

Together,

a+11x = 310000 and we have x from 2.

Hence this is Sufficient.

Answer is C.
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Re: For each month of next year, Company R's monthly revenue target is x [#permalink]
J (January), J + X, J +2X = ?
1) J + 11X = 310,000 Not sufficient.
2) J + 8X = J + 5X + 30,000 ; 3X = 30,000 ; X = 10,000
But do not know J, not sufficient
1) & 2) J + 11*10,000 = 310,000 ; J = 200,000 Done
Answer C.
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Re: For each month of next year, Company R's monthly revenue target is x [#permalink]
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Given: Monthly revenue target is x dollars greater than the target for the previous month
Required: Revenue for March of next year

Statement 1: Target for Dec = 310,000
Target for January = 310,000 + x
Target for February = 310,000 + 2x
Target for March = 310,000 = 3x

But we have no clue about x
INSUFFICIENT

Statement 2: Revenue for September - Revenue for June = 30,000
Hence 3x = 30,000
But we have no idea about the actual revenues.
INSUFFICIENT

Combining both statements:
We know the value of x and we know the value in one of the months,
Hence we can calculate the revenue in March
SUFFICIENT

Correct Option: C
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For each month of next year, Company R's monthly revenue target is x [#permalink]
Hi , Bunuel, Veritas Karishma request to suggest if following method of solving is accurate. Pls suggest if any shortcut to solve to save time.

( Note: Do not make mistake of assuming Jan's revenue as X)

Soln:
Next year let january revenue be J
Then feb revenue will be J+x ( as given revenue target increases by x to previous months target)
March will be J+ x+x= J+ 2x
April will be J+3x and so on....

St 1 says Dec revenue target is 310,000

Dec target in terms of variables above will be J+11x
so we can say J+11x= 310,000

But we do not know what is value of J nor we know value of x . Without which we cannot further find value of March.
Hence St 1 is not sufficient

St 2 Revenue target for September of next year is $30,000 greater than its revenue target for June of next year. June's target =J+5x Sep's target= J+8x as per st 2 J+8x=J+5x+30000 solving this eq, we get x = 10,000 We want to find March's target = J+2x we know value of x but dont know value of J so cannot find . Hence st 2 Not sufficient St1 and St 2 together, J+11x=310,000 and x = 10,000 We can find value of J now by replacing value of x in J+11x=310,000...hence J=200,000 and x =10000 and also cal March's revenue target using value of J and x . March = 220000 Ans is C Tutor Joined: 16 Oct 2010 Posts: 15148 Own Kudos [?]: 66847 [1] Given Kudos: 436 Location: Pune, India Re: For each month of next year, Company R's monthly revenue target is x [#permalink] 1 Kudos Expert Reply tarek99 wrote: For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month. What is Company R's revenue target for March of next year? (1) Company R's revenue target for December of next year is$310,000

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year. Say, Target for Jan = J Target for Feb = J + x Target for March = J + 2x ... Target for Dec = J + 11x We need to find the value of J + 2x. (1) Company R's revenue target for December of next year is$310,000

J + 11x = 310,000
We don't know J and x. Two variables but only 1 equation. Lots of possibilities.

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year. Target for June = J + 5x Target for Sept = J + 8x 3x = 30,000 x = 10,000 We don't know what is J so cannot find J + 2x. Using both, we know x and plugging x in stmnt 1, we can get value of J. So we can find J + 2x. Sufficient. Answer (C) VP Joined: 09 Mar 2016 Posts: 1142 Own Kudos [?]: 1028 [0] Given Kudos: 3851 For each month of next year, Company R's monthly revenue target is x [#permalink] VeritasKarishma wrote: tarek99 wrote: For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month. What is Company R's revenue target for March of next year? (1) Company R's revenue target for December of next year is$310,000

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year. Say, Target for Jan = J Target for Feb = J + x Target for March = J + 2x ... Target for Dec = J + 11x We need to find the value of J + 2x. (1) Company R's revenue target for December of next year is$310,000

J + 11x = 310,000
We don't know J and x. Two variables but only 1 equation. Lots of possibilities.

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year. Target for June = J + 5x Target for Sept = J + 8x 3x = 30,000 x = 10,000 We don't know what is J so cannot find J + 2x. Using both, we know x and plugging x in stmnt 1, we can get value of J. So we can find J + 2x. Sufficient. Answer (C) VeritasKarishma where is it mentioned that revenue was increasing by a constant. it says " R's monthly revenue target is x dollars greater" and as per ST 2 "revenue target for September of next year is$30,000 greater than its revenue target for June of next year" why do you assume that growth of revenue (the value 30K is constant throughout year ?:/ ) it doesnt necessarily mean that each month it was +30K greater than previous one, it could be any number i mean 5k, 10k, 15K 20K etc
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Re: For each month of next year, Company R's monthly revenue target is x [#permalink]
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dave13 wrote:
VeritasKarishma wrote:
tarek99 wrote:
For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month. What is Company R's revenue target for March of next year?

(1) Company R's revenue target for December of next year is $310,000 (2) Company R's revenue target for September of next year is$30,000 greater than its revenue target for June of next year.

Say,
Target for Jan = J
Target for Feb = J + x
Target for March = J + 2x
...
Target for Dec = J + 11x

We need to find the value of J + 2x.

(1) Company R's revenue target for December of next year is $310,000 J + 11x = 310,000 We don't know J and x. Two variables but only 1 equation. Lots of possibilities. (2) Company R's revenue target for September of next year is$30,000 greater than its revenue target for June of next year.

Target for June = J + 5x
Target for Sept = J + 8x
3x = 30,000
x = 10,000
We don't know what is J so cannot find J + 2x.

Using both, we know x and plugging x in stmnt 1, we can get value of J. So we can find J + 2x.
Sufficient.

Answer (C)

VeritasKarishma where is it mentioned that revenue was increasing by a constant. it says " R's monthly revenue target is x dollars greater" and as per ST 2
"revenue target for September of next year is $30,000 greater than its revenue target for June of next year" why do you assume that growth of revenue (the value 30K is constant throughout year ?:/ ) it doesnt necessarily mean that each month it was +30K greater than previous one, it could be any number i mean 5k, 10k, 15K 20K etc You are given that for each month, the target is x more than the preceding month target. "For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month." So if target for Jan in J, target for Feb will be J + x (x more than preceding month i.e. Jan target). If target for Feb is J + x, target for March will be J + x + x (x more than preceding month i.e. Feb target) and so on... Manager Joined: 19 Dec 2020 Posts: 160 Own Kudos [?]: 41 [0] Given Kudos: 316 Re: For each month of next year, Company R's monthly revenue target is x [#permalink] tarek99 wrote: For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month. What is Company R's revenue target for March of next year? (1) Company R's revenue target for December of next year is$310,000

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year. So let initially for Jan, the rev was a$, and for the next 11 months the revenue increases something like this:
a , a+x, a+2x, a+3x , a+4x........ a+11x (Jan till December)

(1) Company R's revenue target for December of next year is $310,000 a+11x= 310000$ (two unknowns, we can't find anything from this one)

Insufficient.

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year. sept: a+8x June= a+5x as per the second statement, a+8x= 30,000+(a+5x) x= 10,000 we need march's revenue, which is a+ 2x, we have x from 2, but we still need "a". Insufficient. 1+2 a+11x= 310000$ , we now have x= 10,000, so we plug that in, we'll get a

once we have a and x both, solving a+2x is as a candy from a kid

C is the answer.
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Re: For each month of next year, Company R's monthly revenue target is x [#permalink]
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Re: For each month of next year, Company R's monthly revenue target is x [#permalink]
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