tarek99 wrote:
For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month. What is Company R's revenue target for March of next year?
(1) Company R's revenue target for December of next year is $310,000
(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year.
So let initially for Jan, the rev was a$, and for the next 11 months the revenue increases something like this:
a , a+x, a+2x, a+3x , a+4x........ a+11x (Jan till December)
(1) Company R's revenue target for December of next year is $310,000
a+11x= 310000$ (two unknowns, we can't find anything from this one)
Insufficient.
(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year.
sept: a+8x
June= a+5x
as per the second statement, a+8x= 30,000+(a+5x)
x= 10,000
we need march's revenue, which is a+ 2x, we have x from 2, but we still need "a".
Insufficient.
1+2
a+11x= 310000$ , we now have x= 10,000, so we plug that in, we'll get a
once we have a and x both, solving a+2x is as a candy from a kid
C is the answer.