For each month of next year, Company R's monthly revenue target is x

Question

For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month. What is Company R's revenue target for March of next year?

(1) Company R's revenue target for December of next year is $310,000

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year.

eschn3am · Accepted Answer

Answer is C

1. We know the target for December is $310,000. We know March is 9 months earlier, but we don't know x.

2. We know X is $10,000 but have no starting point to find March with.

combined we know $310,000 is December
Nov: $300,000
Oct: $290,000
Sep: $280,000
Aug: $270,000
July: $260,000
June: $250,000
May: $240,000
April: $230,000
March: $220,000

or you could just take $310,000 - ($10,000 * 9 months) = $220,000

gixxer1000 · Answer

J=target revenue for January

Stmt 1. J+11x=310,000

Two variables, insuff

Stmt 2. J+9x=J+5x +30,000

Two variables, insuff

Together we have two equations with two variables. Suff

Ans C.

DeeptiM · Answer

Please help me understand how did we calculate x=10,000 from statement 2.

fluke · Answer

It is an arithmetic progression:

Let R be the revenue target for June. 
For July; revenue target=R+x
For August; revenue target=R+2x
For September; revenue target=R+3x

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of mext year.

R+3x-R=30000 
 x=10000 -------------------------1
Not Sufficient.

(1) Company R's revenue target for December of next year is $310,000

Let Jan's revenue target be J,

Common difference is "x". First term(January)=J; Last term or 12th term, say D(December)

A_n=A_1+(n-1)d

D=J+(n-1)x 
 D=J+(12-1)x

310000=J+11x -----2
Not Sufficient.

Using 1 and 2, we get J and we know x.

March Revenue Target= J+2x
Sufficient.

Ans: "C"

Spidy001 · Answer

JAN FEB MAR APR MAY......... .DEC
a a+x a+2x a+11x

a+2x=?
 
1. Not Sufficient
 a+11x = 310000

we dont know a or x. In other words different a , will give different x.

2. Not sufficient

a+8x = 30000 + a+5x

x can be found . But no info on a.

Together,

a+11x = 310000 and we have x from 2.

Hence this is Sufficient.

Answer is C.

thanhtam0102 · Answer

J (January), J + X, J +2X = ?
1) J + 11X = 310,000 Not sufficient.
2) J + 8X = J + 5X + 30,000 ; 3X = 30,000 ; X = 10,000
But do not know J, not sufficient
1) & 2) J + 11*10,000 = 310,000 ; J = 200,000 Done
Answer C.

OptimusPrepJanielle · Answer

Given: Monthly revenue target is x dollars greater than the target for the previous month 
Required: Revenue for March of next year

Statement 1: Target for Dec = 310,000 
Target for January = 310,000 + x 
Target for February = 310,000 + 2x 
Target for March = 310,000 = 3x

But we have no clue about x 
INSUFFICIENT

Statement 2: Revenue for September - Revenue for June = 30,000 
Hence 3x = 30,000 
But we have no idea about the actual revenues. 
INSUFFICIENT

Combining both statements: 
We know the value of x and we know the value in one of the months, 
Hence we can calculate the revenue in March 
SUFFICIENT

Correct Option: C

Kshah001 · Answer

Hi , Bunuel, Veritas Karishma request to suggest if following method of solving is accurate. Pls suggest if any shortcut to solve to save time.

( Note: Do not make mistake of assuming Jan's revenue as X)

Soln:
Next year let january revenue be J 
Then feb revenue will be J+x ( as given revenue target increases by x to previous months target)
 March will be J+ x+x= J+ 2x
 April will be J+3x and so on....

St 1 says Dec revenue target is 310,000
 
 Dec target in terms of variables above will be J+11x
 so we can say J+11x= 310,000
 
But we do not know what is value of J nor we know value of x . Without which we cannot further find value of March.
Hence St 1 is not sufficient

St 2 Revenue target for September of next year is $30,000 greater than its revenue target for June of next year.

June's target =J+5x 
 Sep's target= J+8x
 
as per st 2 J+8x=J+5x+30000
solving this eq, we get x = 10,000

We want to find March's target = J+2x 
we know value of x but dont know value of J so cannot find . Hence st 2 Not sufficient

St1 and St 2 together,

J+11x=310,000 and x = 10,000

We can find value of J now by replacing value of x in J+11x=310,000...hence J=200,000 and x =10000
 and also cal March's revenue target using value of J and x . March = 220000

Ans is C

KarishmaB · Answer

Say, 
Target for Jan = J
Target for Feb = J + x
Target for March = J + 2x
...
Target for Dec = J + 11x

We need to find the value of J + 2x.

(1) Company R's revenue target for December of next year is $310,000

J + 11x = 310,000
We don't know J and x. Two variables but only 1 equation. Lots of possibilities.

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year.

Target for June = J + 5x
Target for Sept = J + 8x
3x = 30,000
x = 10,000
We don't know what is J so cannot find J + 2x.

Using both, we know x and plugging x in stmnt 1, we can get value of J. So we can find J + 2x.
Sufficient.

Answer (C)

dave13 · Answer

VeritasKarishma where is it mentioned that revenue was increasing by a constant. it says " R's monthly revenue target is x dollars greater" and as per ST 2 "revenue target for September of next year is $30,000 greater than its revenue target for June of next year" why do you assume that growth of revenue (the value 30K is constant throughout year ?:/ ) it doesnt necessarily mean that each month it was +30K greater than previous one, it could be any number i mean 5k, 10k, 15K 20K etc

KarishmaB · Answer

You are given that for each month, the target is x more than the preceding month target.

"For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month."

So if target for Jan in J, target for Feb will be J + x (x more than preceding month i.e. Jan target).
If target for Feb is J + x, target for March will be J + x + x (x more than preceding month i.e. Feb target)

and so on...

ueh55406 · Answer

So let initially for Jan, the rev was a$, and for the next 11 months the revenue increases something like this: a , a+x, a+2x, a+3x , a+4x........ a+11x (Jan till December) (1) Company R's revenue target for December of next year is $310,000 a+11x= 310000$ (two unknowns, we can't find anything from this one) Insufficient. (2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year. sept: a+8x June= a+5x as per the second statement, a+8x= 30,000+(a+5x) x= 10,000 we need march's revenue, which is a+ 2x, we have x from 2, but we still need "a". Insufficient. 1+2 a+11x= 310000$ , we now have x= 10,000, so we plug that in, we'll get a once we have a and x both, solving a+2x is as a candy from a kid

C is the answer.

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For each month of next year, Company R's monthly revenue target is x

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For each month of next year, Company R's monthly revenue target is x

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