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(1) There were the same number of beer drinkers as nondrinkers: {Beer} = {Neither} 120 = {Neither} - {Both} + {Neither} 120 = 2*{Neither} - {Both}. Two unknowns. Not sufficient.

(2) The same number of people drank only beer as drank both beer and wine: {Beer} - {Both} = {Both} {Beer} = 2*{Both} 120 = 2*{Both} - {Both} + {Neither} 120 = {Both} + {Neither}. Two unknowns. Not sufficient.

(1)+(2) We have that 120 = 2*{Neither} - {Both} and 120 = {Both} + {Neither}. We have two unknowns and two linear equation, thus we can solve. Sufficient.

Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
21 May 2013, 20:04

I Option A gives us that the no. of people who drink beer is the same as non-drinkers. So there are 160 beer drinker and same no. of non drinkers. We cannot judge the no. of people who neither drink beer or wine as all of these 160 non-beer drinkers could have wine, thereby leaving 0 people who dont have both drinks. NOT SUFFICIENT

II Option B gives us that there are the same no. of only beer drinkers as the no. of drinker of both beer and wine. But, there could be 10 people who drink only beer or there could be 120 and the same no. of people drinking both the beverages

Both taken together gives us that there are 160 people who drink beer. Out of them 80 drink only beer so the other 80 drink both beer and wine. So the no. of guys drinking neither is 320-(160+200-80) So the correct answer will be C _________________

When you feel like giving up, remember why you held on for so long in the first place.

Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
21 May 2013, 20:55

If 320 people attended the wedding and 200 attendees drank wine, how many attendees drank neither beer nor wine? (1) There were the same number of beer drinkers as nondrinkers. (2) The same number of people drank only beer as drank both beer and wine.

As per Set theory, we can write - Total no of Attendees= No of people drinking only Wine+ No of people drinking only BEER - No of people drinking both Wine & Beer + No of people drinking None 320= 200 + Beer only - Both + None 120 = Beer only - Both + None -----(Equation 1)

We need to find the value of NONE Statement 1- Beer only = None By using this info & equation 1 we can not find the value of None. Thus Insufficient

Statement 1- Beer only = Both By using this info & equation 1 we can find the value of None. Thus Sufficient

So the answer for this question has to be B.

Hope this detailed explanation will help many.

Fame _________________

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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
21 May 2013, 21:08

fameatop wrote:

If 320 people attended the wedding and 200 attendees drank wine, how many attendees drank neither beer nor wine? (1) There were the same number of beer drinkers as nondrinkers. (2) The same number of people drank only beer as drank both beer and wine.

As per Set theory, we can write - Total no of Attendees= No of people drinking only Wine+ No of people drinking only BEER - No of people drinking both Wine & Beer + No of people drinking None 320= 200 + Beer only - Both + None 120 = Beer only - Both + None -----(Equation 1)

We need to find the value of NONE Statement 1- Beer only = None By using this info & equation 1 we can not find the value of None. Thus Insufficient

Statement 1- Beer only = Both By using this info & equation 1 we can find the value of None. Thus Sufficient

So the answer for this question has to be B.

Hope this detailed explanation will help many.

Fame

Your equation is wrong as indicated by red part.....Make sure of it Correct one is: Total = Beer dinker + wine drinker - both + Neither _________________

Do not forget to hit the Kudos button on your left if you find my post helpful.

Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
21 May 2013, 21:12

I am confused becasue of the wording of the first statement. What does non drinker mean? Is it the one who does not drink beer or it is referring to the people who drink neither of the drink.

Interpretation of this statement in different ways gives two different answer....

Someone shed some light....

Regards Atal Pandit _________________

Do not forget to hit the Kudos button on your left if you find my post helpful.

(1) There were the same number of beer drinkers as nondrinkers: {Beer} = {Neither} 120 = {Neither} - {Both} + {Neither} 120 = 2*{Neither} - {Both}. Two unknowns. Not sufficient.

(2) The same number of people drank only beer as drank both beer and wine: {Beer} - {Both} = {Both} {Beer} = 2*{Both} 120 = 2*{Both} - {Both} + {Neither} 120 = {Both} + {Neither}. Two unknowns. Not sufficient.

(1)+(2) We have that 120 = 2*{Neither} - {Both} and 120 = {Both} + {Neither}. We have two unknowns and two linear equation, thus we can solve. Sufficient.

Answer: C.

Hope it's clear.

Your solution is awesome..... Could you elaborate the red part? _________________

Do not forget to hit the Kudos button on your left if you find my post helpful.

(1) There were the same number of beer drinkers as nondrinkers: {Beer} = {Neither} 120 = {Neither} - {Both} + {Neither} 120 = 2*{Neither} - {Both}. Two unknowns. Not sufficient.

(2) The same number of people drank only beer as drank both beer and wine: {Beer} - {Both} = {Both} {Beer} = 2*{Both} 120 = 2*{Both} - {Both} + {Neither} 120 = {Both} + {Neither}. Two unknowns. Not sufficient.

(1)+(2) We have that 120 = 2*{Neither} - {Both} and 120 = {Both} + {Neither}. We have two unknowns and two linear equation, thus we can solve. Sufficient.

Answer: C.

Hope it's clear.

Your solution is awesome..... Could you elaborate the red part?

The second statement states that {Beer} - {Both} = {Both} thus {Beer} = 2*{Both}. Now, substitute {Beer} = 2*{Both} into 120 = {Beer} - {Both} + {Neither} to get 120 = 2*{Both} - {Both} + {Neither}.

(1) There were the same number of beer drinkers as nondrinkers: {Beer} = {Neither} 120 = {Neither} - {Both} + {Neither} 120 = 2*{Neither} - {Both}. Two unknowns. Not sufficient.

(2) The same number of people drank only beer as drank both beer and wine: {Beer} - {Both} = {Both} {Beer} = 2*{Both} 120 = 2*{Both} - {Both} + {Neither} 120 = {Both} + {Neither}. Two unknowns. Not sufficient.

(1)+(2) We have that 120 = 2*{Neither} - {Both} and 120 = {Both} + {Neither}. We have two unknowns and two linear equation, thus we can solve. Sufficient.

Answer: C.

Hope it's clear.

could you solve it for me please so i can see how this works out

(1) There were the same number of beer drinkers as nondrinkers: {Beer} = {Neither} 120 = {Neither} - {Both} + {Neither} 120 = 2*{Neither} - {Both}. Two unknowns. Not sufficient.

(2) The same number of people drank only beer as drank both beer and wine: {Beer} - {Both} = {Both} {Beer} = 2*{Both} 120 = 2*{Both} - {Both} + {Neither} 120 = {Both} + {Neither}. Two unknowns. Not sufficient.

(1)+(2) We have that 120 = 2*{Neither} - {Both} and 120 = {Both} + {Neither}. We have two unknowns and two linear equation, thus we can solve. Sufficient.

Answer: C.

Hope it's clear.

could you solve it for me please so i can see how this works out

Sum the equations: 240 = 3*{Neither} --> {Neither} = 80.

Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
05 Oct 2014, 05:38

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