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If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths

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Bunuel
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If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths [#permalink] New post   28 Apr 2016, 01:18
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If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths digits, respectively, what is the value of b?

(1) If 5a.b were rounded to the nearest whole number, the new number would be 52.
(2) 5a.b/9 converts to a terminating decimal.
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Abhini26
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Re: If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths [#permalink] New post   28 Apr 2016, 02:49
Ans is d..
Statment 1 is insufficient by itself as no unique sol is generated. a can be 1,2 and b can be 0-9 depending on value of a.
Statment 2 is insufficient by itself. However we can deduce that a+b = 4, 13.
On combining both statments a unique sol is obtained

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Re: If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths [#permalink] New post   23 May 2017, 01:31
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Bunuel wrote:
If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths digits, respectively, what is the value of b?

(1) If 5a.b were rounded to the nearest whole number, the new number would be 52.
(2) 5a.b/9 converts to a terminating decimal.


from (1), it could be any no. for eg-51.6, 51.7, 51.8, 51.9 =>not sufficient.
from (2), it could be any no. for eg-58.5, 50.4, 54.9, etc (the sum of digits should be divisible by 9 as the decimal is terminating) =>not sufficient
from (1) & (2), it could 52.2 only (the no. 51.3 if you are thinking can be rounded to 51 & not 52).
So, b=2 =>(1) & (2) together sufficient.
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Re: If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths [#permalink] New post   25 Dec 2018, 01:56
VeritasKarishma amanvermagmat Bunuel chetan2u gmatbusters Abhishek009 Gladiator59

Can you advise if below line of thoughts is correct:
for a fraction to reduce to terminating decimal, I need either 2 or 5 OR BOTH
in the denominator, since st 2 has 9 in the denominator and WE ARE GIVEN that the
fraction reduces to terminating decimal, we need to cancel out 9 i.e. we must have
multiple of 9 in the numerator.

Let me know our thoughts choosing on B vs C
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If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths [#permalink] New post   Updated on: 19 Sep 2019, 06:01
Statement one & two both are not sufficient alone.

But when taken together, the only possible value where we get terminating decimal is 52.2. Both can be rounded to 52.

Answer: C

Originally posted by navzie on 18 Sep 2019, 15:43.
Last edited by navzie on 19 Sep 2019, 06:01, edited 1 time in total.
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Re: If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths [#permalink] New post   19 Sep 2019, 02:15
Statement 1 alone can be any of these 51.5, 51.6, 51.7.....52.1, 52.2,52.3,52.4 So it's not sufficient.

Statement 2 alone can be 50.5, 54.0, 54.9 etc so not sufficient.

St 1+2: 52.2 is the only option that is divisible by 9 (sum of digits should be divisible by 3 and 9). Hence sufficient.

Ans C

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Re: If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths [#permalink] New post   17 Nov 2023, 19:28
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Re: If 5a.b is a decimal with 5, a, and b as the tens, ones, and tenths [#permalink]
17 Nov 2023, 19:28
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