LM wrote:

If n is one of the numbers in \(\frac{1}{3}\), \(\frac{3}{16}\), \(\frac{4}{7}\), \(\frac{3}{5}\) then what is the value of n?

(1) \(\frac{5}{16}<n<\frac{7}{12}\)

(2) \(\frac{7}{13}<n<\frac{19}{33}\)

I find it easier to convert the fractions into decimal form

1/3= 0.3333

3/16= 0.1875 ( Easier way to do this will be, we know 1/8 = 0.125 and so 1/16 = 0.0625 ----> 0.0625*3= 0.1875)

4/7 = 0.568 ( 1/7 = 0.142857...consider only 0.142 as the given options are not so close)

3/5 = 0.6

From st 1 we have 5/16< n< 7/12 can be converted to 0.3125 < n < 0.583...

we see that 2 values are possible ie 1/3 or 4/7 and hence st 1 ruled out

st 2 7/13< n< 19/33 -----> 0.49<n< 0.577

Another way to look at it will be , Since the largest fraction is 3/5 which is 0.6,we can calculate 60% of 33 which is 19.8 but since the numerator in the fraction (19/33) is 19 which is less than 19.8 and thus we will have only one value in the range Only 1 value that is 4/7 is in this range

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