Last visit was: 19 Nov 2025, 07:48 It is currently 19 Nov 2025, 07:48
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
LM
Joined: 03 Sep 2006
Last visit: 04 Apr 2015
Posts: 444
Own Kudos:
7,671
 [14]
Given Kudos: 33
Posts: 444
Kudos: 7,671
 [14]
2
Kudos
Add Kudos
12
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,389
Own Kudos:
778,253
 [8]
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,389
Kudos: 778,253
 [8]
2
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
General Discussion
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,389
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,389
Kudos: 778,253
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
WoundedTiger
Joined: 25 Apr 2012
Last visit: 25 Sep 2024
Posts: 521
Own Kudos:
2,534
 [2]
Given Kudos: 740
Location: India
GPA: 3.21
WE:Business Development (Other)
Products:
Posts: 521
Kudos: 2,534
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
LM
If n is one of the numbers in \(\frac{1}{3}\), \(\frac{3}{16}\), \(\frac{4}{7}\), \(\frac{3}{5}\) then what is the value of n?

(1) \(\frac{5}{16}<n<\frac{7}{12}\)

(2) \(\frac{7}{13}<n<\frac{19}{33}\)


I find it easier to convert the fractions into decimal form
1/3= 0.3333
3/16= 0.1875 ( Easier way to do this will be, we know 1/8 = 0.125 and so 1/16 = 0.0625 ----> 0.0625*3= 0.1875)
4/7 = 0.568 ( 1/7 = 0.142857...consider only 0.142 as the given options are not so close)
3/5 = 0.6

From st 1 we have 5/16< n< 7/12 can be converted to 0.3125 < n < 0.583...

we see that 2 values are possible ie 1/3 or 4/7 and hence st 1 ruled out

st 2 7/13< n< 19/33 -----> 0.49<n< 0.577

Another way to look at it will be , Since the largest fraction is 3/5 which is 0.6,we can calculate 60% of 33 which is 19.8 but since the numerator in the fraction (19/33) is 19 which is less than 19.8 and thus we will have only one value in the range Only 1 value that is 4/7 is in this range
User avatar
SatvikVedala
Joined: 03 Oct 2022
Last visit: 03 May 2025
Posts: 177
Own Kudos:
121
 [1]
Given Kudos: 51
Posts: 177
Kudos: 121
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
LM
If n is one of the numbers in \(\frac{1}{3}\), \(\frac{3}{16}\), \(\frac{4}{7}\), \(\frac{3}{5}\) then what is the value of n?

(1) \(\frac{5}{16}<n<\frac{7}{12}\)

(2) \(\frac{7}{13}<n<\frac{19}{33}\)

From Question stem 1/3, 3/16, 4/7,3/5 are the given numbers

Option 1) \(\frac{5}{16}<n<\frac{7}{12}\)

LCM of 16, 12 is 48
\(\frac{5}{16}*48 <n*48 <\frac{7}{12}*48\)
Implies,
15 <n*48 < 28

\(\frac{1}{3}\)*48 = 16 -- lies in range

\(\frac{3}{16}\)*48 = 9 -- doesn't lie in the range

\(\frac{4}{7}\)*48 = 27.42 -- lies in the range

\(\frac{3}{5}\)*48 = 28.8 -- doesn't lie in the range

Option 2) \(\frac{7}{13}<n<\frac{19}{33}\)
LCM of 13, 33 is 429
\(\frac{7}{13}*429 <n*429 <\frac{19}{33}*429\)
Implies,
231 <n*429 < 247

\(\frac{1}{3}\)*429 = 143 -- doesn't lie in the range

\(\frac{3}{16}\)*429 = approx. 90 -- doesn't lie in the range

\(\frac{4}{7}\)*429 = approx. 244 -- lies in the range

\(\frac{3}{5}\)*429 = approx. 255 -- doesn't lie in the range

therefore answer is B
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,588
Own Kudos:
Posts: 38,588
Kudos: 1,079
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Math Expert
105389 posts
496 posts