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if p and q are integers, can p/q be written as a decimal

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CEO
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if p and q are integers, can p/q be written as a decimal [#permalink] New post 16 Dec 2003, 16:52
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E

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if p and q are integers, can p/q be written as a decimal with finite digits

a. q/p can be written as a finite decimal

b. both p and q are multiples of 120.
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 [#permalink] New post 16 Dec 2003, 19:17
Is it E?

1) q/p could be written as finite digits: Tells us nothing because p/q could be 1/3 and be an infinite digit; whereas, q/p would be a finite digit.

2) p and q both multiples: no insufficient because you can have 240/480 which is terminating or 240/360 which is non terminating.

Combine them both and you can still have either terminating or non-terminating digits.
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 [#permalink] New post 16 Dec 2003, 19:25
E would be then answer

1) Say p=4 and q=7 Then true that q/p is finite (1.75) but p/q would not be. If you pick p=4 and q=8 Then it is true that both q/p and p/q are finite. Thus statement 1 is not sufficient to answer the question.

2) Say p=360 and q =600 Then q/p is not a finite decimal. However, if p=360 and q=720 then you obtain p/q=0.5 which is a finite decimal. Statement 2 alone is not sufficient to answer the question.

Combining both statements together will not help any better so E should be the answer. Am I right?
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 [#permalink] New post 17 Dec 2003, 06:14
praetorian,

Did you write this question?
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 [#permalink] New post 17 Dec 2003, 06:29
stoolfi wrote:
praetorian,

Did you write this question?


is it that bad? :(
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 [#permalink] New post 17 Dec 2003, 06:54
Nope, not bad at all-- just had a different "feel"
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 [#permalink] New post 17 Dec 2003, 07:58
I guess the answer is E? :?:
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 [#permalink] New post 23 Dec 2003, 16:03
I think the answer is C.

(1) p = 2, q = 3 => q/p is finite, p/q is not finite, so the snwer to thequestion is NO.

p = 5, q = 2 > q/p is finite, p/q is also finite, answer is YES

NOT SUFF

(2) p = 120, 240, 360,......
q = 120, 240, 360, ......

p = 120, q = 360 => p/q = 1/3, the answer is NO
p = 120, q = 240 => p/q = 1.2, the answer is YES

NOT SUFF

TOGETHER

p = 120, 240, 360,......
q = 120, 240, 360, ......

AND q/p is finite decimal.

So if q = 120, then p = 120, 240, 480, 600,.... (please note that 360 is not possible here)

So possible values of p/q are 1, 2, 4, 5, . ... answer YES

if q= 240, then p = 120, 240, 480, .. (no 360 possible this time as well)

So the answer will be YES in this case also.

I think answer is C. Is there any easy way out?

Thanks
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 [#permalink] New post 30 Dec 2003, 01:56
gmatblast wrote:
I think the answer is C.

(1) p = 2, q = 3 => q/p is finite, p/q is not finite, so the snwer to thequestion is NO.

p = 5, q = 2 > q/p is finite, p/q is also finite, answer is YES

NOT SUFF

(2) p = 120, 240, 360,......
q = 120, 240, 360, ......

p = 120, q = 360 => p/q = 1/3, the answer is NO
p = 120, q = 240 => p/q = 1.2, the answer is YES

NOT SUFF

TOGETHER

p = 120, 240, 360,......
q = 120, 240, 360, ......

AND q/p is finite decimal.

So if q = 120, then p = 120, 240, 480, 600,.... (please note that 360 is not possible here)

So possible values of p/q are 1, 2, 4, 5, . ... answer YES

if q= 240, then p = 120, 240, 480, .. (no 360 possible this time as well)

So the answer will be YES in this case also.

I think answer is C. Is there any easy way out?

Thanks


nice solution

i didnt see see any errors
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 [#permalink] New post 30 Dec 2003, 08:13
What if q is 1080 and p is 120?

This would be repeating. Is 1080 off limits for some reason?
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 [#permalink] New post 10 Jan 2004, 21:17
what if q = 360 and p = 480
q/p = 6/8 ( finite decimal )
but p/q cannot be a finite decimal.
Shouldn't the answer be E ?
  [#permalink] 10 Jan 2004, 21:17
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