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# If the positive integer x is a multiple of 4?

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Manager
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If the positive integer x is a multiple of 4? [#permalink]

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02 Dec 2006, 07:01
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If the positive integer x is a multiple of 4 and the positive integer y is a multiple of 6, then xy must be a multiple of which of the following?

I. 8
II. 12
III 18

A) II only
B) I and II only
C) I and III only
D) II and III only
E) I, II and III

Official Guide 12 Question

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02 Dec 2006, 07:06
nah, not necessarily:

Ans B.

From question x/4 is an integer.

x/4 = 2*2*q/4 ---> where q is the integer

Also y/6 = p => y/6 = 2*3*p/6

So, xy = 2*2*2*3 *pq

Thus 2*2*2 = 8 and 2*3*2 = 12 satisfy
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02 Dec 2006, 07:38
B for me

x/4 = integer or 4p/4 = integer and y/6 = integer or yq/6 = integer

x and y are positive integers so limiting factor is when x and y are at theier minumum. Min values of x and y are when p=q=1
4*1 = 4 6*1 = 6
4*6 = 24

Hence multipe of 8 and 12
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11 Sep 2011, 11:24
xy = 4 * 6 = 2 * 2 * 2 * 3 = 8 * 3 = 2 * 12

We can see that xy is a multiple of both 8 and 12, but not 18.

Option (B)
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11 Sep 2011, 11:52
GyanOne wrote:
xy = 4 * 6 = 2 * 2 * 2 * 3 = 8 * 3 = 2 * 12

We can see that xy is a multiple of both 8 and 12, but not 18.

Option (B)

@GyanOne - LCM of 4 and 6 = 12 or if I compare as mentioned in the below series... I can see only multiple of 12.
Multiple of 4 - 4, 8, [highlight]12[/highlight], 16, 20, [highlight]24[/highlight]...
Multiple of 6 - 6, [highlight]12[/highlight], 18, [highlight]24[/highlight]...

Can you pls elaborate more?
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11 Sep 2011, 15:08
x is a multiple of 4 = 4p

y is a multiple of 6 = 6q

=> xy = 24pq

by quick observation we can see 8 and 12 are factors of 24. so i and iii must be true.

also 24 = 2*2*2*3

so xy may or may not have 18 as a factor depending on the values of p and q.

if p or q = 3 , then 18 is also a factor xy.
if p and q do not have 3, then 18 is not a factor or xy.

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12 Sep 2011, 02:36
simple way to answer these questions is to pick multiples of 4 and 6 and compare with answers.
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15 Sep 2011, 13:49
I did the prime factor box method:

4= 2*2
6= 2*3

so all factors of x has to have 2*2 in it and y has to have 2*3 in it.

lets look at our options

i) 8= 2*2*2. If we look at our prime factor boxes above we see that we have to have at least three 2's. (two in 4 and one in 6) so yes 8 is a multiple.

ii) 12= 2*2*3. Again if we look at our prime factor boxes above we see that it contains 2*2*3.

iii) 18= 2*3*3. For 18 we need two 3's and if you look at your prime factor boxes you see that we only have one 3, therefore 18 is not an option.

B both i and ii
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Re: If the positive integer x is a multiple of 4? [#permalink]

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05 May 2012, 02:11
Hello,

quick question, I got the answer right, though I am having some problems with the "plug in numbers" approach here. Can anybody help real quick with an example?

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Re: If the positive integer x is a multiple of 4? [#permalink]

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05 May 2012, 03:40
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andih wrote:
Hello,

quick question, I got the answer right, though I am having some problems with the "plug in numbers" approach here. Can anybody help real quick with an example?

If the positive integer x is a multiple of 4 and the positive integer y is a multiple of 6, then xy must be a multiple of which of the following?
I. 8
II. 12
III 18

A. II only
B. I and II only
C. I and III only
D. II and III only
E. I, II and III

First of all notice that we are asked $$xy$$ MUST be a multiple of which of the following, not COULD be a multiple.

$$x$$ is a multiple of 4 --> $$x=4m$$, for some positive multiple $$m$$, so $$x$$ can be: 4, 8, 12, ...
$$y$$ is a multiple of 6 --> $$y=6n$$, for some positive multiple $$n$$, so $$y$$ can be: 6, 12, 18, ...

So, $$xy=(4m)*(6n)=24mn$$, so $$xy$$ is in any case a multiple of 24, which means it must be a multiple of 8 and 12, but not necessarily of 18. For example the least value of $$x$$ is 4 and the least value of $$y$$ is 6, so the least value of $$xy$$ is 24, which is a multiple of both 8 and 12, but not 18.

Hope it's clear.
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Re: If the positive integer x is a multiple of 4? [#permalink]

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07 May 2012, 16:52
ellisje22 wrote:
If the positive integer x is a multiple of 4 and the positive integer y is a multiple of 6, then xy must be a multiple of which of the following?

I. 8
II. 12
III 18

A) II only
B) I and II only
C) I and III only
D) II and III only
E) I, II and III

Official Guide 12 Question

 Question: 23 Page: 23 Difficulty: 600

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Video Explanations:

Hello
I try !
X can be written as X=2x2K where K is a whole number which belongs to R
Y can be written as Y= 3X2 L where L is a whole number which belongs to R
HENCE XY can BE WRITTEN as 2x2x3x2xKxL

Hence XY must be a multiple of 8 and 12
For 18 we misse a 3

Hope I am right

best regards
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Re: If the positive integer x is a multiple of 4? [#permalink]

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05 Aug 2014, 23:50
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Re: If the positive integer x is a multiple of 4? [#permalink]

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13 Mar 2016, 12:32
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Re: If the positive integer x is a multiple of 4?   [#permalink] 13 Mar 2016, 12:32
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