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Is x<0? (1) x^2-x > 0 (2) |x| > 1

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Is x<0? (1) x^2-x > 0 (2) |x| > 1 [#permalink] New post 06 Apr 2004, 23:24
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Is x<0?


(1) x^2-x > 0
(2) |x| > 1
Senior Manager
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Re: DS-20 [#permalink] New post 08 Apr 2004, 16:48
hallelujah1234 wrote:
Is x<0?


(1) x^2-x > 0
(2) |x| > 1


(1) R - [0, 1]
(2) R - [-1, 1]


Answer is E
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 [#permalink] New post 22 May 2004, 05:03
anyone else want to explain this?
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 [#permalink] New post 23 May 2004, 08:39
This is my first post, so don't beat me, please. :-D
As I see it
1. gives 2 possible areas for X because x(x-1)>0
a. x>0, x>1 so x>1
b. x<0, x<1 so x<0

2. x<-1, x>1
Therefore E. is correct
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 [#permalink] New post 23 May 2004, 09:07
elena wrote:
This is my first post, so don't beat me, please. :-D
As I see it
1. gives 2 possible areas for X because x(x-1)>0
a. x>0, x>1 so x>1
b. x<0, x<1 so x<0

2. x<-1, x>1
Therefore E. is correct


hi elena

welcome to gmat club. thanks for your explanation.
  [#permalink] 23 May 2004, 09:07
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