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Bunuel wrote: charlemagne wrote: ilhom1986 wrote: From the given question I found that IF A>0 than C>0 IF A<0 than C<0 (I answered this question in less than a minute and choose B, because I didn't consider B to be equal to zero) Good question for GMAT starter, easy to get into trap...  I did this sometime back...bt I dont seem to have considered that B may be equal to 0, and still chose C. CAn anyone show how B=0 case make a difference? Sure. For example if we put b\neq{0} in the stem then the answer would become B, instead of C. IF THE QUESTION WERE:If b\neq{0} is a^7*b^2*c^3>0 ? Since b\neq{0} then b^2>0, so we can reduce by it (b^2 does not affect given inequality at all) and the question becomes: is a^7*c^3>0? So, the question basically asks whether a and c have the same sign. (Notice that if b\neq{0} were not given then b^2\geq{0}, and we could not reduce by it) (1) bc<0. Not sufficient. (2) ac>0 --> a and c have the same sign. Sufficient. Answer: B. Hope it's clear. P.S. Solution to he original question is given here: m11-75085.html#p1073868Yes....much clearer....Thank you!!! Another kudos to you.... BTW, with so many of these already on your name, you must be going crazy with the amount of auto-notification emails coming your way??
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charlemagne wrote: Yes....much clearer....Thank you!!! Another kudos to you.... BTW, with so many of these already on your name, you must be going crazy with the amount of auto-notification emails coming your way?? That's not a problem. Also one should consider kudos not only as a "thank you" to user whose post was helpful, but also as a tool to distinguish a valuable post. Notice that posts with more than 1 kudos have different color, also notice that total # of kudos is shown just beside the topic name, so by giving a kudos to a post you are drawing an attention of other users to the helpful material and thus are contributing to the community.
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Bunuel wrote: charlemagne wrote: Yes....much clearer....Thank you!!! Another kudos to you.... BTW, with so many of these already on your name, you must be going crazy with the amount of auto-notification emails coming your way?? That's not a problem. Also one should consider kudos not only as a "thank you" to user whose post was helpful, but also as a tool to distinguish a valuable post. Notice that posts with more than 2 kudos have different color, also notice that total # of kudos is shown just beside the topic name, so by giving a kudos to a post you are drawing an attention of other users to the helpful material and thus are contributing to the community. Gee...didnt know that...thanks for the info bunuel! Quote: lso notice that total # of kudos is shown just beside the topic name, Didn't get this part though.
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Here is how: Question: Is (A^7) * (B^2) * (C^3) > 0?
Statement 1: BC < 0 Evaluate the Y/N question: Is (A^7) * (B*C)^2 * (C) > 0? (B*C)^2 > 0 But, if A > 0 and C > 0 then expression > 0 => Yes However, if A > 0 and C < 0 then expression < 0 => No So, S1 is not sufficient. Eliminate A and D.
Statement 2: AC > 0 Evaluate the Y/N question: Is expression (A^7) * (B^2) * (C^3) > 0?
Combine A and C.
Is (A*C)^3 * A^4 * B^2 > 0
S2 says A*C > 0 ; so (A*C)^3 > 0 A^4 is always positive even if A were negative; so A^4 > 0 B^2 is always positive even if B were negative; so B^2 > 0 So, the expression is always positive even if A and/or B were negative. expression > 0
Only exception to this is: if B = 0, then expression = 0 S2 is NOT sufficient.
Take both S1 and S2. This eliminate the possibility that B may be 0. So, C is correct.
Last edited by vshrivastava on 23 Apr 2013, 06:59, edited 1 time in total.
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vshrivastava wrote: I'm sorry if I'm missing something, but I think the right answer is B.
Here is how: Question: Is (A^7) * (B^2) * (C^3) > 0?
Statement 1: BC < 0 Evaluate the Y/N question: Is (A^7) * (B*C)^2 * (C) > 0? (B*C)^2 > 0 But, if A > 0 and C > 0 then expression > 0 => Yes However, if A > 0 and C < 0 then expression < 0 => No So, S1 is not sufficient. Eliminate A and D.
Statement 2: AC > 0 Evaluate the Y/N question: Is (A^7) * (B^2) * (C^3) > 0?
Combine A and C.
Is (A*C)^3 * A^4 * B^2 > 0
S2 says A*C > 0 ; so (A*C)^3 > 0 A^4 is always positive even if A were negative; so A^4 > 0 B^2 is always positive even if B were negative; so B^2 > 0
So, the expression is always positive even if A and/or B were negative. S2 is sufficient.
B is correct.
What do you guys think? Notice that when we consider the second statement we know nothing about the value of b, so if b=0, then a^7*b^2*c^3=0 ( a^7*b^2*c^3 is NOT greater than 0). That's why (2) is not sufficient. Similar questions to practice: is-x-2-y-5-z-0-1-xz-y-0-2-y-z-98341.htmlis-x-7-y-2-z-3-0-1-yz-0-2-xz-127692.htmlm21-q30-96613.htmlHope it helps.
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Answer C.
Rule out A, B and D immediately as both will be required.
So there are two outcomes based on (1) and (2):
Outcome 1: A = +ve, B = -ve, C = +ve
Gives: (+ve)^7 x (-ve)^2 x (+ve)^3 = (+ve) x (+ve) x (+ve) = +ve
OR
Outcome 2: A = -ve, B = +ve, C = -ve (i.e. opposite of outcome 1)
Gives: (-ve)^7 x (+ve)^2 x (-ve)^3 = (-ve) x (+ve) x (-ve) = +ve
So answer is C, as both possible options give the answer i.e. A^7 x B^2 x C^3 > 0
BUT TOOK ME 4:00mins TO GET THERE!!!
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topmbaseeker wrote: Is A^7 B^2 C^3 > 0 ? 1. BC < 0 2. AC > 0 Source: GMAT Club Tests - hardest GMAT questions I did the question too quick to fall in the trap. Very good question!. C is correct. A^7*B^2*C^3 = (A^6*B^2*C^2)*(C*A) If B = 0, (A^6*B^2*C^2)*(C*A) = 0. If B #0, the sign of (A^6*B^2*C^2)*(C*A) depends on (C*A) We must combine statement 1 and 2 to conclude: B #0 and (C*A) > 0 ==> (A^6*B^2*C^2)*(C*A) > 0.
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[quote="topmbaseeker"]Is A^7 B^2 C^3 > 0 ?
1. BC < 0 2. AC > 0
for AC>0 either both are negative or positive we dont have depend on value of B,bcause square of anything is positive in this case if A and c ARE NEGATIVE THEN 2 NEGATIVE SIGNS LEFT CANCEL OUT EACH OTHER AND SQUARE OF B IS POSITIVE,SO ANSWER IS POSITIVE AND IF A AND C ARE POSITIVE AGAIN SQUARE OF B IS POSITIVE so answer is B
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I think the answer is B, S2 alone is sufficient.
A^7, B^2, C^3 can be considered individually.
S1 cannot account for A at all, and A^7 could be either positive or negative so S1 is out.
Looking at S2, B^2 is automatically positive, so we have only A^7 and C^3 to worry about. Since AC>0, then (AC)^3>0 so we have only A^4 to worry about, but A^4 is positive by definition.
So S2 alone is sufficient. S1 doesn't work at all.
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