Is integer \(x\) even?
1.) \((x + 1)(x - 2)\) is even
2.) \((x - 3)(x + 5)\) is even
OA is C
I disagree. X could be 3 such that statement 2 is 0. As 0 is an even integer x could be even or odd. So OA should be E
OA is B and I think it's correct.
Do you still think B is NOT sufficient alone? If yes, please explain why?
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