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11 Jul 2011, 07:57
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Is integer \(x\) even?
1.) \((x + 1)(x - 2)\) is even
2.) \((x - 3)(x + 5)\) is even
1.) \((x + 1)(x - 2)\) is even
2.) \((x - 3)(x + 5)\) is even
OA is C
I disagree. X could be 3 such that statement 2 is 0. As 0 is an even integer x could be even or odd. So OA should be E
I disagree. X could be 3 such that statement 2 is 0. As 0 is an even integer x could be even or odd. So OA should be E
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11 Jul 2011, 14:44
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heyholetsgo
OA is B and I think it's correct.
Do you still think B is NOT sufficient alone? If yes, please explain why?
I too say it's B.
Knowing that X is an integer:
Stmt 1) if (X-2) is odd then (X+1) is even and (X-2)(X+1) is even and X is odd.
If (X-2) is even then (X+1) is odd and (X-2)(X+1) is even and X is even.
This tells us X is even or odd. Not sufficient.
Stmt 2 - For (X+3)(X+5) to be even, X has to be odd.
NB: If X is an integer and X is odd, X+1 has to be even and X-1 has to be even.
Knowing that X is an integer:
Stmt 1) if (X-2) is odd then (X+1) is even and (X-2)(X+1) is even and X is odd.
If (X-2) is even then (X+1) is odd and (X-2)(X+1) is even and X is even.
This tells us X is even or odd. Not sufficient.
Stmt 2 - For (X+3)(X+5) to be even, X has to be odd.
NB: If X is an integer and X is odd, X+1 has to be even and X-1 has to be even.
