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# Machine X takes 20 hours longer than machine Y to produce 10

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Machine X takes 20 hours longer than machine Y to produce 10 [#permalink]

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02 Mar 2011, 14:23
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Machine X takes 20 hours longer than machine Y to produce 1080 Widgets. Machine Y produces 20 percent more widgets in an hour than machine x does in an hour. How many widgets per hour does machine X produce

A. 100
B. 65
C. 25
D. 11
E. 9
[Reveal] Spoiler: OA

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02 Mar 2011, 15:02
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Machine X rate : x wid / hr
Machine Y rate : y wid / hr
Given y = 1.2 x --------(1)

1080 / x - 1080 / y = 20 ----(2)
1) + 2)
Solving get x = 9 wid / hr

rxs0005 wrote:
Machine X takes 20 hours longer than machine Y to produce 1080 Widgets.
Machine Y produces 20 percent more widgets in an hour than machine x does in an hour. How many widgets per hour does machine X produce

100

65

25

11

9
Director
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02 Mar 2011, 15:05
Back solving -
Equation (2) reduces to 54/x - 54/y = 1. Hence x should be a factor of 54. E it is.
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03 Mar 2011, 18:22
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rxs0005 wrote:
Machine X takes 20 hours longer than machine Y to produce 1080 Widgets.
Machine Y produces 20 percent more widgets in an hour than machine x does in an hour. How many widgets per hour does machine X produce

100

65

25

11

9

Another approach:Use Ratios

Machine Y produces 20% more widgets so its speed is 6/5 of X.
Speed of X: Speed of Y = 5:6
Time taken by X: Time taken by Y = 6:5 (if amount of work is kept constant, time will be inversely proportional to speed)
This difference of 1 in their time accounts for 20 hrs.
Hence X takes 6*20 = 120 hrs to produce 1080 widgets. In 1 hour, it produces 1080/120 = 9 widgets.
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews SVP Joined: 16 Nov 2010 Posts: 1672 Location: United States (IN) Concentration: Strategy, Technology Followers: 33 Kudos [?]: 514 [2] , given: 36 Re: Word problem [#permalink] ### Show Tags 03 Mar 2011, 21:37 2 This post received KUDOS My take : Machine Y -> Y hrs to produce 1080 Widgets, So Machine X -> Y + 20 to produce 1080 Widgets Y -> 1080/Y Widgets X -> 1080/(Y+20) 1/Y = 1.2 * 1/(y+20) 5y + 100 = 6y => y = 100, so Machine X - 120 hrs to 1080 hence Machine X -> 1080/120 = 9 _________________ Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant) GMAT Club Premium Membership - big benefits and savings Senior Manager Joined: 08 Nov 2010 Posts: 417 WE 1: Business Development Followers: 7 Kudos [?]: 105 [0], given: 161 Re: Word problem [#permalink] ### Show Tags 05 Mar 2011, 09:26 Karishma, can u explain ur system in more details plz? y produces 20% faster so as far as i understand if x produces 5 Y produces 6/5 in one hour. hmm - im stuck. ill be happy to learn ur way - ur ways are amazing. thanks.+1 _________________ Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7119 Location: Pune, India Followers: 2131 Kudos [?]: 13631 [0], given: 222 Re: Word problem [#permalink] ### Show Tags 05 Mar 2011, 19:45 144144 wrote: Karishma, can u explain ur system in more details plz? y produces 20% faster so as far as i understand if x produces 5 Y produces 6/5 in one hour. hmm - im stuck. ill be happy to learn ur way - ur ways are amazing. thanks.+1 What I use a lot is ratios. Ratios eliminate the need for equations. In different questions, you will need to handle data differently to get a ratio. e.g. 1. Speed of x is 40 m/hr and speed of y is 60 m/hr. Then ratio of speeds is 40:60 i.e. 2:3 (lowest representation - in ratios 2:3 is same as 4:6 which is same as 20:30 etc) 2. Speed of x is 20% more than that of y. If speed of y is 1, speed of x is 6/5 (i.e. 20% = 1/5 more than 1). Ratio of speed of X:Y = 6/5:1 or 6:5 (Multiplying the ratio by 5) or simply, since speed of x is more, x will be 6 and y will be 5. Now, quantities such as time, rate and work done are related to each other. We know W = R*T If two machines A and B with rates of work in the ratio 6:5 work for 1 hr each, who will do more work? Since they are both working for the same time, A will do more work since its rate is higher. How much more work will A do as compared to B? Since A's rate is 20% higher, A will do 20% more work... Now, let me ask you this - if both A and B do the same amount of work, who will take less time? Since A's rate is 20% more, A will take less time. How much less time will it take? Let's say there was 30 units of work that each did. A's rate - 6 units/hr, time taken - 30/6 = 5 hrs B's rate - 5 units/hr, time taken - 30/5 = 6 hrs So basically time taken flips the speed (time is inversely proportional to speed) Time taken by A:B = 5:6 Now think, I tell you that A takes 10 hrs to do a job. How long will B take to do the same job? 12 hrs because they take time in the ratio 5:6. Now, if I tell you that for a particular work, difference between time taken by A and time taken by B is 10 hrs. How long did A take to finish the job? Since the difference between the times should be 10, they must have taken 50 and 60 hrs to do the work. These are a few concepts that we use to solve questions using ratios. The next topic I am taking up on my Veritas blog is ratios. Watch out for the first post early next week... It should make these concepts clearer... _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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05 Mar 2011, 23:45
VeritasPrepKarishma wrote:
Another approach:Use Ratios

Machine Y produces 20% more widgets so its speed is 6/5 of X.
Speed of X: Speed of Y = 5:6
Time taken by X: Time taken by Y = 6:5 (if amount of work is kept constant, time will be inversely proportional to speed)
This difference of 1 in their time accounts for 20 hrs.
Hence X takes 6*20 = 120 hrs to produce 1080 widgets. In 1 hour, it produces 1080/120 = 9 widgets.

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03 Dec 2012, 01:25
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Rate of X = $$\frac{1080}{y+20}=w$$
Rate of Y = $$\frac{1080}{y}=1.2w$$

Combine:
$$\frac{1080}{y+20}(1.2) = \frac{1080}{y}$$
$$y+20=1.2y==>.2y=20==>y=100$$

$$\frac{1080}{100+20}=\frac{1080}{120}=9$$

9 widgets in 1 hour.
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Re: Machine X takes 20 hours longer than machine Y to produce 10 [#permalink]

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12 Feb 2014, 12:52
Here's a short and elegant way to solve

1/x - 1/y = 20 / 1080 = 1/54

y = 1.2x

1/x - 1/1.2x = 1/54

1/6x = 54

x = 9

But let me tell you that I really liked Karishma's approach using ratios too.

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Re: Machine X takes 20 hours longer than machine Y to produce 10 [#permalink]

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30 Mar 2015, 09:42
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Re: Machine X takes 20 hours longer than machine Y to produce 10 [#permalink]

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31 Mar 2015, 02:25
rxs0005 wrote:
Machine X takes 20 hours longer than machine Y to produce 1080 Widgets. Machine Y produces 20 percent more widgets in an hour than machine x does in an hour. How many widgets per hour does machine X produce

A. 100
B. 65
C. 25
D. 11
E. 9

Machine Y produces 20 percent more widgets in an hour than machine x does in an hour.
So if machine X produces 100 widgets, then machine Y produces 120 widgets.
Ratio of 120/100 = 6/5.
This is their speed of work (Y:X).
i.e. speed of their work (X:Y) = 5/6

Now, time is inversely proportional to speed.
Hence the ratio of the time spent (X:Y)= 6/5
Let us assume that they spend 6x and 5x hours.
Given that 6x-5x = 20
So, x = 20.
Hence 6x = 6*20 = 120 hours.
Hence X takes 120 hours to produce 1080 widgets.
So, in 1 hour, it can produce (1 * 1080)/120
= 9

Hence option (E).
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Re: Machine X takes 20 hours longer than machine Y to produce 10 [#permalink]

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04 Apr 2015, 05:18
rxs0005 wrote:
Machine X takes 20 hours longer than machine Y to produce 1080 Widgets. Machine Y produces 20 percent more widgets in an hour than machine x does in an hour. How many widgets per hour does machine X produce

A. 100
B. 65
C. 25
D. 11
E. 9

I think the fastest way to solve such problem is to do POE:
Find out the factors of 1080 = 2x2x2x3x3x3x3x3x5

To get the per hour rate for each machine, it has to be a factor of 1080. In the answer choices, we can see only 9 satisfies the criteria.
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Machine X takes 20 hours longer than machine Y to produce 10 [#permalink]

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04 Apr 2015, 05:52
rxs0005 wrote:
Machine X takes 20 hours longer than machine Y to produce 1080 Widgets. Machine Y produces 20 percent more widgets in an hour than machine x does in an hour. How many widgets per hour does machine X produce

A. 100
B. 65
C. 25
D. 11
E. 9

machine X takes 20 hrs more to produce 1080 widgets
OR
machine X takes 1 hr more to produce 54 widgets

54/X - 1 =54/1.2X

54/X - 54/1.2X = 1

now we can solve this quadratic equation , but we do not need to . 54 is divisible only by 9 in the answer options, so lets substitute X=9
6 - 5 = 1 .

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Re: Machine X takes 20 hours longer than machine Y to produce 10 [#permalink]

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17 Oct 2016, 08:14
Hello from the GMAT Club BumpBot!

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Re: Machine X takes 20 hours longer than machine Y to produce 10   [#permalink] 17 Oct 2016, 08:14
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