anjanapadmaraj wrote:
In a town of 10 million households there are 3 newspapers in circulation - X, Y and Z. There are 9 million households that subscribe to one or more newspapers.The number of total circulation of all the newspapers is 12 million. The number of households subscribing to X,Y are 2 million and 5 million respectively. What is the number of households subscribing to more than 1 newspaper.Assume that any household subscribes only one newspaper of a particular type.
a. At least 3 million
b. Exactly 3 million
c. Less than 3 million
d. At least 2 million
e. At least 1.5 million.
12 mil is the number of newspapers distributed.
9 mil is the number of households in which they are distributed.
Since each household gets at least one paper, say 9 mil are distributed, one each, in the 9 mil households. We are left with 3 mil newspapers. Each one of these 3 mil papers is distributed as second/third paper in some household.
Let's focus on distributing just these 3 mil papers now.
The maximum number of households in which these 3 mil papers can be distributed is 3 mil. Each paper goes to a different household. So number of households subscribing to more than 1 newspaper is \(\leq 3\)mil. But there is no such option.
Say, if I give 2 papers (a total of 3 papers) in the same household, and the rest of them in different households, how many households will get covered? (3 mil - 1)
How can I minimize the total number of households? By giving 2 papers in as many households (a total of 3 papers) as possible. If I give 2 papers in each household, I will need to cover 1.5 mil households. So number of households receiving more than 1 paper should be at least 1.5 mil.
Answer (E)