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Re: Some people claim to experience a bitter taste whenever they [#permalink]
anshunadir wrote:
IMO C.
Paragraph 2 talks about synesthetes who see black 5s as red 5s and black 2s as green 2s.

Option C talks about similar settings:
Quote:
C. Subjects are shown a set of black 5s randomly scattered among a field of black 2s and asked to identify as many
5s as they can in ten seconds.


BTW what's the OA.

OA is ....
par2 talks about the ease with which synethetes identify triangular black 2's among a field of black 5's.
Option C, however, talks about random black 5's among a field of black 2's. Since the synethetes are more
perceptual in differentiating these colors, they would be better in the arrangement in C...

What's your line of reasoning?
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Re: Some people claim to experience a bitter taste whenever they [#permalink]
I got it right, but it took me around 7 minutes to get the answer.
The correct answer is C.

Reasoning:

As per the passage "Several black 2s were arranged to form a triangle among a field of black 5s. In cases where the synesthesia is genuinely perceptual, subjectsshould easily see the triangle."
Only option C talks about the number of 5s, rest all the options talk about the shape of 5s.
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Re: Some people claim to experience a bitter taste whenever they [#permalink]
C seems to be the answer.
And one can find answer by reading these lines" Recently, researchers used a pop-out test to determine whether synesthesia is truly perceptual. Subjects claiming to experience red whenever they see a black 5 and green with every black 2 were given the following test. Several black 2s were arranged to form a triangle among a field of black 5s".
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Some people claim to experience a bitter taste whenever they [#permalink]
gmatbull wrote:
anshunadir wrote:
IMO C.
Paragraph 2 talks about synesthetes who see black 5s as red 5s and black 2s as green 2s.

Option C talks about similar settings:
Quote:
C. Subjects are shown a set of black 5s randomly scattered among a field of black 2s and asked to identify as many
5s as they can in ten seconds.


BTW what's the OA.

OA is ....
par2 talks about the ease with which synethetes identify triangular black 2's among a field of black 5's.
Option C, however, talks about random black 5's among a field of black 2's. Since the synethetes are more
perceptual in differentiating these colors, they would be better in the arrangement in C...

What's your line of reasoning?


I will try to explain my line of reasoning. C is correct because in the passage it is mentioned that synethetes see black 5s as red and black 2s as green. Also, in the beginning of the passage it is stated that when you have a number of green objects and red objects, if scientists ask you to find red ones, red items will pop out, meaning that you will not pay attention to green ones and will be more efficient in counting them. So, if we combine the two statements, synethetes should do better at these tests because they see black 5s and 2s as distinct colors, and hence can count them much faster as opposed to a regular person, who cannot count them efficiently because all he sees is black 2s and 5s, which "blend in".

With this logic, it will be apparent that other choices are wrong in some way. Just keep those above mentioned pieces of information in mind and analyze them.
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Some people claim to experience a bitter taste whenever they [#permalink]
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