Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Join Our "Master Multi-Source Reasoning Questions by Owning the Dataset” Session! Tackling Multi-Source Reasoning (MSR) on the GMAT can be like navigating through a complex maze.
Join us for an exclusive live interview with Piyush, who achieved an impressive GMAT FE 735, securing the coveted 100th percentile! Gain invaluable insights and actionable tips to elevate your own GMAT performance. Don’t miss out!
Earning a 100th percentile score on the GMAT Focus is no easy feat. But with Target Test Prep, any score is possible. Take Ming, a TTP student who recently scored 755 (Q86/V88/DI86) on the GMAT Focus Edition.
Achieving a high GMAT score while balancing a hectic work life is challenging, but with the right strategy, it's absolutely possible. Discover the ultimate GMAT study strategy designed exclusively for working professionals.
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
Sam and Angela decide to join a Dance club. The club
[#permalink]
31 Jul 2006, 08:04
1. Sam and Angela decide to join a Dance club. The club includes 7 women and 7 men (including Sam and Angela). The club decides to select a woman and a man to lead the dance group. What is the probability that Sam and Angela will NOT be selected.
The Way to do this would be 1- 1/7* 1/7... But I wanted to ask that the ORDER is not important here and hence should the probab for them to be selected be 2/49 instead of 1/49.
2. What is the probab of selecting a woman and a man from a group of 7 women and 7 men.
Would this be 7C1 * 7C1/14C2 (As order does not matter here)
Basically what is the difference between the above two questions which makes the aproach different.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Re: Sam and Angela decide to join a Dance club. The club
[#permalink]
31 Jul 2006, 08:16
Here is my understanding of the problem and solution.
Let's first try to find probability of the opposite event: either Sam or Angela (or both) are selected to lead the dance.
There are 7 women (including Angela) to form a possible pair with Sam.
There are 6 men (excluding Sam, who was already counted above) to pair with Angela. So, we have 13 possible pairs including either Sam or Angela.
Re: Sam and Angela decide to join a Dance club. The club
[#permalink]
31 Jul 2006, 20:03
v1rok wrote:
Here is my understanding of the problem and solution.
Let's first try to find probability of the opposite event: either Sam or Angela (or both) are selected to lead the dance.
There are 7 women (including Angela) to form a possible pair with Sam. There are 6 men (excluding Sam, who was already counted above) to pair with Angela. So, we have 13 possible pairs including either Sam or Angela.
Total number of pairs is 7x7=49.
So, the probability is 1 - 13/49 = 36/49
its sam and angela ---- not sam or angela - its basically the couple is not selected.
Re: Sam and Angela decide to join a Dance club. The club
[#permalink]
31 Jul 2006, 20:15
v1rok wrote:
Here is my understanding of the problem and solution.
Let's first try to find probability of the opposite event: either Sam or Angela (or both) are selected to lead the dance.
There are 7 women (including Angela) to form a possible pair with Sam. There are 6 men (excluding Sam, who was already counted above) to pair with Angela. So, we have 13 possible pairs including either Sam or Angela.
Total number of pairs is 7x7=49.
So, the probability is 1 - 13/49 = 36/49
its sam and angela ---- not sam or angela - its basically the couple is not selected.
Re: Sam and Angela decide to join a Dance club. The club
[#permalink]
31 Jul 2006, 20:52
Oops... Even though I provided correct justification in the post just above this one, I had solved for the wrong event in my original post at the top. Of course, the answer is 48/49. I just need to learn how to read properly...
Schools:Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Q50 V34
Send PM
Re: Sam and Angela decide to join a Dance club. The club
[#permalink]
03 Aug 2006, 09:21
sumitsarkar82 wrote:
1. Sam and Angela decide to join a Dance club. The club includes 7 women and 7 men (including Sam and Angela). The club decides to select a woman and a man to lead the dance group. What is the probability that Sam and Angela will NOT be selected.
The Way to do this would be 1- 1/7* 1/7... But I wanted to ask that the ORDER is not important here and hence should the probab for them to be selected be 2/49 instead of 1/49.
2. What is the probab of selecting a woman and a man from a group of 7 women and 7 men.
Would this be 7C1 * 7C1/14C2 (As order does not matter here)
Basically what is the difference between the above two questions which makes the aproach different.
Two questions are altogether different.
In the first question you can select any male except Sam AND can select any female except Angela. Th egroup of two must have one male and one female.
Total cases = 7C1 * 7C1 = 49
How many cases when Sam and Angela are selected = 1
Prob of NOT selecting these two = 1-1/49 = 48/49
Second question is asking the probability of selecting a particular man and a particular woman out of 7 men and 7 women.
In how many ways you can select any man and any women = 7C1 * 7C1 = 49
Ways when a particular man and a particular woman are selected = 1
Prob = 1/49
If second question asks: What is the probabilty of selecting 2 people from 7 men and 7 women so that the group of 2 have 1 man and 1 woman then the answer is
Total cases = 14C2 = 91
Cases when both are men = 7C2 = 21
Cases when both are women = 7C2 = 21
Cases when one is man and one is woman = 91 -42 = 49
Prob = 49/91 or 7C1 * 7C1/14C2
Hope this helps.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
gmatclubot
Re: Sam and Angela decide to join a Dance club. The club [#permalink]