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Graph, Cirlce and Triangle Question

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piper
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Graph, Cirlce and Triangle Question [#permalink] New post   08 Oct 2008, 13:24
Attachment:
graph question.JPG


In the figure, points P & Q lie on the circle with Center O. What is the value of S?
(A) 1/2 (B) 1 (C) Square Root of 2 (D) Square Root of 3 (E) (Square Root of 2)/2

What's the easiest way to answer this question??? Is there a rule?



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Re: Graph, Cirlce and Triangle Question [#permalink] New post   08 Oct 2008, 13:49
piper wrote:
Attachment:
graph question.JPG


In the figure, points P & Q lie on the circle with Center O. What is the value of S?
(A) 1/2 (B) 1 (C) Square Root of 2 (D) Square Root of 3 (E) (Square Root of 2)/2

What's the easiest way to answer this question??? Is there a rule?


not sure f this approach is right but..

notice that the triangle POQ is 90 and therefore P is going to be reciprocal to Q
therefore
s=1
t=sqrt3

only way to solve this in less then 2 minute gmat time
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Re: Graph, Cirlce and Triangle Question [#permalink] New post   08 Oct 2008, 13:58
spiridon wrote:
not sure f this approach is right but..

notice that the triangle POQ is 90 and therefore P is going to be reciprocal to Q
therefore
s=1
t=sqrt3

only way to solve this in less then 2 minute gmat time


Thanks and 1 is the correct ans. I guess it's just a rule. Really weird why it's not sqrt3. But I will move on. Thanks again.
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Re: Graph, Cirlce and Triangle Question [#permalink] New post   08 Oct 2008, 14:04
piper wrote:
spiridon wrote:
not sure f this approach is right but..

notice that the triangle POQ is 90 and therefore P is going to be reciprocal to Q
therefore
s=1
t=sqrt3

only way to solve this in less then 2 minute gmat time


Thanks and 1 is the correct ans. I guess it's just a rule. Really weird why it's not sqrt3. But I will move on. Thanks again.



sure and the graph tricks u to assume that the answer is sqrt3 because it seems that x cuts the triangle into halves

however, if thats the case the coordinates would be exactly the same eg 1, 1

given the difference between sqrt 3 and 1 or 1.4 and 1 one can spot that the values need to be reciprocal

only way i can think of without using a calculator and complex sin cos calculations
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Re: Graph, Cirlce and Triangle Question [#permalink] New post   08 Oct 2008, 14:46
7-t71146
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Re: Graph, Cirlce and Triangle Question [#permalink] New post   08 Oct 2008, 17:54
pawan's link is the best explanation. That's what made sense to me when I did this problem some time ago.
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Re: Graph, Cirlce and Triangle Question [#permalink] New post   31 Jan 2009, 15:43
OP is perpendicular to OQ, therefore when multiply them you get -1.
The slope of OP is 1/(-sqrt3)
Therefore 1/(-sqrt3) * its -ve reciprocal = -1
which is: 1/(-sqrt3) * (sqrt3)/1 = -1

note that 1/(-sqrt3) = y/-x
and (sqrt3)/1 = y/-(-x), therefore s =1



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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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Re: Graph, Cirlce and Triangle Question [#permalink]
31 Jan 2009, 15:43
Moderator:
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