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piper
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Graph, Cirlce and Triangle Question 08 Oct 2008, 13:24
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Attachment:
graph question.JPG

In the figure, points P & Q lie on the circle with Center O. What is the value of S?
(A) 1/2 (B) 1 (C) Square Root of 2 (D) Square Root of 3 (E) (Square Root of 2)/2

What's the easiest way to answer this question??? Is there a rule?



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Graph, Cirlce and Triangle Question 08 Oct 2008, 13:49
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Attachment:
graph question.JPG

In the figure, points P & Q lie on the circle with Center O. What is the value of S?
(A) 1/2 (B) 1 (C) Square Root of 2 (D) Square Root of 3 (E) (Square Root of 2)/2

What's the easiest way to answer this question??? Is there a rule?
Show more

not sure f this approach is right but..

notice that the triangle POQ is 90 and therefore P is going to be reciprocal to Q
therefore
s=1
t=sqrt3

only way to solve this in less then 2 minute gmat time
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Graph, Cirlce and Triangle Question 08 Oct 2008, 13:58
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spiridon
not sure f this approach is right but..

notice that the triangle POQ is 90 and therefore P is going to be reciprocal to Q
therefore
s=1
t=sqrt3

only way to solve this in less then 2 minute gmat time
Show more

Thanks and 1 is the correct ans. I guess it's just a rule. Really weird why it's not sqrt3. But I will move on. Thanks again.
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Graph, Cirlce and Triangle Question 08 Oct 2008, 14:04
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piper
spiridon
not sure f this approach is right but..

notice that the triangle POQ is 90 and therefore P is going to be reciprocal to Q
therefore
s=1
t=sqrt3

only way to solve this in less then 2 minute gmat time

Thanks and 1 is the correct ans. I guess it's just a rule. Really weird why it's not sqrt3. But I will move on. Thanks again.
Show more


sure and the graph tricks u to assume that the answer is sqrt3 because it seems that x cuts the triangle into halves

however, if thats the case the coordinates would be exactly the same eg 1, 1

given the difference between sqrt 3 and 1 or 1.4 and 1 one can spot that the values need to be reciprocal

only way i can think of without using a calculator and complex sin cos calculations
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Graph, Cirlce and Triangle Question 08 Oct 2008, 14:46
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Graph, Cirlce and Triangle Question 08 Oct 2008, 17:54
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pawan's link is the best explanation. That's what made sense to me when I did this problem some time ago.
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Graph, Cirlce and Triangle Question 31 Jan 2009, 15:43
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OP is perpendicular to OQ, therefore when multiply them you get -1.
The slope of OP is 1/(-sqrt3)
Therefore 1/(-sqrt3) * its -ve reciprocal = -1
which is: 1/(-sqrt3) * (sqrt3)/1 = -1

note that 1/(-sqrt3) = y/-x
and (sqrt3)/1 = y/-(-x), therefore s =1



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!