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Graph, Cirlce and Triangle Question

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Intern
Joined: 30 Sep 2008
Posts: 10
Graph, Cirlce and Triangle Question [#permalink]

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08 Oct 2008, 12:24
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

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graph question.JPG [ 3.89 KiB | Viewed 1266 times ]

In the figure, points P & Q lie on the circle with Center O. What is the value of S?
(A) 1/2 (B) 1 (C) Square Root of 2 (D) Square Root of 3 (E) (Square Root of 2)/2

What's the easiest way to answer this question??? Is there a rule?
Senior Manager
Joined: 04 Aug 2008
Posts: 372
Re: Graph, Cirlce and Triangle Question [#permalink]

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08 Oct 2008, 12:49
piper wrote:
Attachment:
graph question.JPG

In the figure, points P & Q lie on the circle with Center O. What is the value of S?
(A) 1/2 (B) 1 (C) Square Root of 2 (D) Square Root of 3 (E) (Square Root of 2)/2

What's the easiest way to answer this question??? Is there a rule?

not sure f this approach is right but..

notice that the triangle POQ is 90 and therefore P is going to be reciprocal to Q
therefore
s=1
t=sqrt3

only way to solve this in less then 2 minute gmat time
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Intern
Joined: 30 Sep 2008
Posts: 10
Re: Graph, Cirlce and Triangle Question [#permalink]

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08 Oct 2008, 12:58
spiridon wrote:
not sure f this approach is right but..

notice that the triangle POQ is 90 and therefore P is going to be reciprocal to Q
therefore
s=1
t=sqrt3

only way to solve this in less then 2 minute gmat time

Thanks and 1 is the correct ans. I guess it's just a rule. Really weird why it's not sqrt3. But I will move on. Thanks again.
Senior Manager
Joined: 04 Aug 2008
Posts: 372
Re: Graph, Cirlce and Triangle Question [#permalink]

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08 Oct 2008, 13:04
piper wrote:
spiridon wrote:
not sure f this approach is right but..

notice that the triangle POQ is 90 and therefore P is going to be reciprocal to Q
therefore
s=1
t=sqrt3

only way to solve this in less then 2 minute gmat time

Thanks and 1 is the correct ans. I guess it's just a rule. Really weird why it's not sqrt3. But I will move on. Thanks again.

sure and the graph tricks u to assume that the answer is sqrt3 because it seems that x cuts the triangle into halves

however, if thats the case the coordinates would be exactly the same eg 1, 1

given the difference between sqrt 3 and 1 or 1.4 and 1 one can spot that the values need to be reciprocal

only way i can think of without using a calculator and complex sin cos calculations
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Joined: 27 Jun 2008
Posts: 538
WE 1: Investment Banking - 6yrs
Re: Graph, Cirlce and Triangle Question [#permalink]

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08 Oct 2008, 13:46
Director
Joined: 26 Mar 2008
Posts: 652
Schools: Duke 2012
Re: Graph, Cirlce and Triangle Question [#permalink]

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08 Oct 2008, 16:54
pawan's link is the best explanation. That's what made sense to me when I did this problem some time ago.
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Manager
Joined: 02 Aug 2007
Posts: 222
Schools: Life
Re: Graph, Cirlce and Triangle Question [#permalink]

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31 Jan 2009, 14:43
OP is perpendicular to OQ, therefore when multiply them you get -1.
The slope of OP is 1/(-sqrt3)
Therefore 1/(-sqrt3) * its -ve reciprocal = -1
which is: 1/(-sqrt3) * (sqrt3)/1 = -1

note that 1/(-sqrt3) = y/-x
and (sqrt3)/1 = y/-(-x), therefore s =1
Re: Graph, Cirlce and Triangle Question   [#permalink] 31 Jan 2009, 14:43
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Graph, Cirlce and Triangle Question

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