If x, y, and z are consecutive even positive integers, which

Hi All,

The key to answering this question quickly is to realize that X+Y+Z is a multiple of BOTH 2 and 3. With that information, you can quickly eliminate answer choices. If you don't recognize those two Number Properties though, then you can still get to the correct answer (but it will require a bit more work).

We're told that X, Y and Z are CONSECUTIVE EVEN INTEGERS, so we could write them algebraically as...

A + (A+2) + (A+4) = 3A + 6

We know that 3A + 6 COULD equal one of those five answers; we just have to find it...

Could 3A + 6 = 141
3A = 135
A = 45
This is NOT an EVEN INTEGER, so 141 is NOT the answer

Could 3A + 6 = 200
3A = 194
A = 64.6666
This is NOT an EVEN INTEGER, so 200 is NOT the answer

Could 3A + 6 = 318
3A = 312
A = 104
This IS an EVEN INTEGER! The numbers would be 104, 106 and 108. This IS the answer

Final Answer:

GMAT assassins aren't born, they're made,
Rich

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.