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Re: If x, y, and z are consecutive even positive integers, which [#permalink]

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27 Dec 2014, 03:23

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The key to answering this question quickly is to realize that X+Y+Z is a multiple of BOTH 2 and 3. With that information, you can quickly eliminate answer choices. If you don't recognize those two Number Properties though, then you can still get to the correct answer (but it will require a bit more work).

We're told that X, Y and Z are CONSECUTIVE EVEN INTEGERS, so we could write them algebraically as...

A + (A+2) + (A+4) = 3A + 6

We know that 3A + 6 COULD equal one of those five answers; we just have to find it...

Could 3A + 6 = 141 3A = 135 A = 45 This is NOT an EVEN INTEGER, so 141 is NOT the answer

Could 3A + 6 = 200 3A = 194 A = 64.6666 This is NOT an EVEN INTEGER, so 200 is NOT the answer

Could 3A + 6 = 318 3A = 312 A = 104 This IS an EVEN INTEGER! The numbers would be 104, 106 and 108. This IS the answer

Re: If x, y, and z are consecutive even positive integers, which [#permalink]

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21 Jan 2017, 23:06

Take the three consecutive even numbers as x-2,x and x+2. So the sum is 3x. So the problem boils down to: Which of the answer choices is a multiple of 3. Job done.
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Re: If x, y, and z are consecutive even positive integers, which
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21 Jan 2017, 23:06

Campus visits play a crucial role in the MBA application process. It’s one thing to be passionate about one school but another to actually visit the campus, talk...

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