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A company bought a load of water-damaged copy paper,
[#permalink]
11 Aug 2003, 10:14
A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?
Archived Topic
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Re: A company bought a load of water-damaged copy paper,
[#permalink]
11 Aug 2003, 10:29
Brainless wrote:
A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?
.64
.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.
Re: A company bought a load of water-damaged copy paper,
[#permalink]
11 Aug 2003, 15:21
mciatto wrote:
Brainless wrote:
A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?
.64
.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.
48 * 4/3 = 64 to get the answer.
Your answer is right. But still I am unable to see it !!
A detailed explanation plz !!
Re: A company bought a load of water-damaged copy paper,
[#permalink]
11 Aug 2003, 15:38
Brainless wrote:
mciatto wrote:
Brainless wrote:
A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?
.64
.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.
48 * 4/3 = 64 to get the answer.
Your answer is right. But still I am unable to see it !! A detailed explanation plz !!
Let C = cost of the reams
Let R = original number of reams.
C = (2/3)R * .72 [Cost = number of good reams x cost per good ream]
C = (3/4)R * X [Cost = number of good reams x cost per good ream]
The "cost" of the paper is the same in both cases so:
(2/3)R * .72 = (3/4)R * X
Now solve for X.
X = (2/3)(4/3)* .72 = .64.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
gmatclubot
Re: A company bought a load of water-damaged copy paper, [#permalink]