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# A company bought a load of water-damaged copy paper,

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Manager
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11 Aug 2003, 10:14
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be \$0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?
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Brainless

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11 Aug 2003, 10:18
I remember I saw it in Princeton. A problem with a twist. I hate it.

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11 Aug 2003, 10:29
Brainless wrote:
A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be \$0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?

.64

.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.

48 * 4/3 = 64 to get the answer.

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11 Aug 2003, 15:21
mciatto wrote:
Brainless wrote:
A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be \$0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?

.64

.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.

48 * 4/3 = 64 to get the answer.

Your answer is right. But still I am unable to see it !!
A detailed explanation plz !!
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11 Aug 2003, 15:38
Brainless wrote:
mciatto wrote:
Brainless wrote:
A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be \$0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?

.64

.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.

48 * 4/3 = 64 to get the answer.

Your answer is right. But still I am unable to see it !!
A detailed explanation plz !!

Let C = cost of the reams
Let R = original number of reams.

C = (2/3)R * .72 [Cost = number of good reams x cost per good ream]
C = (3/4)R * X [Cost = number of good reams x cost per good ream]

The "cost" of the paper is the same in both cases so:

(2/3)R * .72 = (3/4)R * X

Now solve for X.

X = (2/3)(4/3)* .72 = .64.
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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Re: Problem Solving 1   [#permalink] 11 Aug 2003, 15:38
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# A company bought a load of water-damaged copy paper,

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