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A company bought a load of water-damaged copy paper, 11 Aug 2003, 10:14
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A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?



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A company bought a load of water-damaged copy paper, 11 Aug 2003, 10:18
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A company bought a load of water-damaged copy paper, 11 Aug 2003, 10:29
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Brainless
A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?


.64

.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.

48 * 4/3 = 64 to get the answer.
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A company bought a load of water-damaged copy paper, 11 Aug 2003, 15:21
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mciatto
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A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?

.64

.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.

48 * 4/3 = 64 to get the answer.


Your answer is right. But still I am unable to see it !!
A detailed explanation plz !!
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A company bought a load of water-damaged copy paper, 11 Aug 2003, 15:38
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mciatto
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A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?

.64

.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.

48 * 4/3 = 64 to get the answer.

Your answer is right. But still I am unable to see it !!
A detailed explanation plz !!


Let C = cost of the reams
Let R = original number of reams.

C = (2/3)R * .72 [Cost = number of good reams x cost per good ream]
C = (3/4)R * X [Cost = number of good reams x cost per good ream]

The "cost" of the paper is the same in both cases so:

(2/3)R * .72 = (3/4)R * X

Now solve for X.

X = (2/3)(4/3)* .72 = .64.



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