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Manager
Joined: 11 Aug 2012
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f(x)=x^3+3x^2−6x+2
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danzig wrote:

f(x)=x^3+3x^2−6x+2

$$x^3 + 3x^2 − 6x + 2 = (x-1)(x^2 + 4x - 2)$$
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Manager
Joined: 11 Aug 2012
Posts: 134
Schools: HBS '16, Stanford '16
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Kudos [?]: 50 [0], given: 16

PareshGmat wrote:
danzig wrote:

f(x)=x^3+3x^2−6x+2

$$x^3 + 3x^2 − 6x + 2 = (x-1)(x^2 + 4x - 2)$$

Thank you!, could you explain it step by step? thanks!
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Expert's post
danzig wrote:

f(x)=x^3+3x^2−6x+2

Here is a post that tells you how to factor third degree: http://www.veritasprep.com/blog/2013/09 ... rd-degree/

f(x)=x^3+3x^2−6x+2

Try x = 0, 1, -1 etc.
x = 1 works

$$x^3+3x^2 - 6x+2 = (x - 1)*(x^2 + 4x - 2)$$
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