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Please, your help. How to factorize this función? Thanks!

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Please, your help. How to factorize this función? Thanks! [#permalink] New post 31 Aug 2014, 22:46
Please, your help. How to factorize this función? Thanks!

f(x)=x^3+3x^2−6x+2
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Re: Please, your help. How to factorize this función? Thanks! [#permalink] New post 31 Aug 2014, 23:06
danzig wrote:
Please, your help. How to factorize this función? Thanks!

f(x)=x^3+3x^2−6x+2


\(x^3 + 3x^2 − 6x + 2 = (x-1)(x^2 + 4x - 2)\)
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Re: Please, your help. How to factorize this función? Thanks! [#permalink] New post 01 Sep 2014, 07:19
PareshGmat wrote:
danzig wrote:
Please, your help. How to factorize this función? Thanks!

f(x)=x^3+3x^2−6x+2


\(x^3 + 3x^2 − 6x + 2 = (x-1)(x^2 + 4x - 2)\)


Thank you!, could you explain it step by step? thanks!
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Please, your help. How to factorize this función? Thanks! [#permalink] New post 03 Sep 2014, 21:51
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danzig wrote:
Please, your help. How to factorize this función? Thanks!

f(x)=x^3+3x^2−6x+2


Here is a post that tells you how to factor third degree: http://www.veritasprep.com/blog/2013/09 ... rd-degree/

f(x)=x^3+3x^2−6x+2

Try x = 0, 1, -1 etc.
x = 1 works

\(x^3+3x^2 - 6x+2 = (x - 1)*(x^2 + 4x - 2)\)
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Please, your help. How to factorize this función? Thanks!   [#permalink] 03 Sep 2014, 21:51
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