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Re: How many different ways can 2 students be seated in a row of [#permalink]
But that yields the same answer as 4C2? How do you solve use combinations or perm?

That comb above does not take into account the empty seat.
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Re: How many different ways can 2 students be seated in a row of [#permalink]
Take two cases.

case 1... 2 spaces in between that means C1 _ _ C2 or C2_ _ C1

case 2.... 1 space in between.
now consider c1_c2 as one element
Number of ways of arranging these in 4 seats = \(2p2*2!\) = 4

2p2 because we have considered c1_c2 as one element , 2! is rearrangement between c1 and c2

total = 6..whats OA?
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Re: How many different ways can 2 students be seated in a row of [#permalink]
ksharma12 wrote:
How many different ways can 2 students be seated
in a row of 4 desks, so that there is always at
least one empty desk between the students?

(A) 2
(B) 3
(C) 4
(D) 6
(E) 12
Easy Question I know. Explanation please?


Possible patterns = 1x2x, 1xx2, x1x2, 2x1x, x2x1, 2xx1 = 6 hence D

Whats the OA
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Re: How many different ways can 2 students be seated in a row of [#permalink]
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Total cases : 12 ( student one has 4 options and student two has three options, 4x3=12)
Non-favourable cases : 6 (when two students sit together. students in desk 1 and desk 2 , in desk 2 and desk 3, in desk 3 and desk 4) for each of these cases there are two possibilities because the positions can be interchanged. hence 2x3=6.

SO favourable cases : 12-6=6.
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How many different ways can 2 students be seated in a row of [#permalink]
It is important to see that the empty desks are not distinct (I missed this the first time, because I considered them to be)
We have "4" students (2 normal students {\(A\),\(B\)} and 2 students {\(E_1\),\(E_2\)} that we can consider empty desks) and 4 places.
Total = \(\frac{4!}{2!}\) since \(AE_1E_2B=AE_2E_1B\)
Cases in which the two students are together {{\(A\),\(B\)}, \(E_1\), \(E_2\)} = 3!*2!/2! since \(ABE_1E_2\) = \(ABE_2E_1\)
Total - together = 12 - 6 = 6
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Re: How many different ways can 2 students be seated in a row of [#permalink]
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Hi All,

Since the answers to this question are all small, and the question has a strong 'visual' component to it, we can 'brute force' the answer by drawing some pictures.

If we call the two students 'X' and 'Y', we have the following possibilities:

X _ Y _
Y _ X _

X _ _ Y
Y _ _ X

_ X _ Y
_ Y _ X

Total options: 6

Final Answer:

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Re: How many different ways can 2 students be seated in a row of [#permalink]
Students: A, B
Desks: _ _ _ _
Case 1: A _ B _ (A&B can switch places) : 2 Ways
Case 2: _ A _ B ( A&B can switch places) : 2 Ways
Case 3: A _ _ B (A &b B can switch places): 2 Ways

Total Ways: 2 + 2 + 2 = 6
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Re: How many different ways can 2 students be seated in a row of [#permalink]
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Re: How many different ways can 2 students be seated in a row of [#permalink]
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