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Re: As shown in the figure above, a thin conveyor belt 15 feet long is [#permalink]
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GMAT_700 wrote:
A thin conveyor belt 15feet long is drawn tightly around two circular wheels each 1 foot in diameter. What is the distance, in feet, between the centers of the two wheels?

The correct answer is (15-pi)/ 2


the circumference covered by the belt of each circle = 1/2 (2 pi r/2) = 1/2 (2 pi 1/2) = pi/2
the total circumference of both circles covered by the belt = pi
the lenth of the distance belt that doesnot cover the circumferences of 2 circles = 15 - pi
so the distance between the centers of the circles = (15 - pi)/2

drawing a picture would be an easy way to understand why half of (15 - pi) is the distance between the centers of two circles.
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As shown in the figure above, a thin conveyor belt 15 feet long is dra [#permalink]
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As shown in the figure above, a thin conveyor belt 15 feet long is drawn tightly around two circular wheels each 1 foot in diameter. What is the distance, in feet, between the centers of the two wheels?

A) \(\frac{15-\pi}{2}\)
B) \(\frac{5\pi}{4}\)
C) \(15-2\pi\)
D) \(15-\pi\)
E) \(2\pi\)
Attachments

Conveyer Belt.jpg
Conveyer Belt.jpg [ 5.75 KiB | Viewed 125914 times ]


Originally posted by reply2spg on 29 Jul 2009, 19:35.
Last edited by ENGRTOMBA2018 on 16 Jul 2015, 06:56, edited 1 time in total.
Edited the question, added the OA and tags
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Re: As shown in the figure above, a thin conveyor belt 15 feet long is dra [#permalink]
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The length of the belt = (semi perimeter of circle1) + 2* distance between the centres of the circles + (semi perimeter of circle2)

let's say the distance between the centres of the circles = d.
since both the circles have diameter = 1 ft ,therefore their radius = .5ft
therefore semiperimeter of each of the circles = (1/2) * 2* pi * r
= pi* .5
so,
15 = (pi* .5) + 2d + (pi*.5)
15 = pi + 2d
therefore d = (15-pi)/2

Hence option A
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Re: As shown in the figure above, a thin conveyor belt 15 feet long is dra [#permalink]
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Total length=15 ft
both cricles are consuming= pi length=(half circumfrence of c1 + half circumfrence of c2)
Circumference= 2*pi*r
r=d/2=1/2
Half circumference=pi/2
Both circles consume=2*pi/2=pi
Now to find distance between two centers=(15-pi) is twice distance from centers of two circles.
therefore actual distance=(15-pi)/2
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Re: As shown in the figure above, a thin conveyor belt 15 feet long is [#permalink]
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GMAT_700 wrote:

As shown in the figure above, a thin conveyor belt 15 feet long is drawn tightly around two circular wheels each 1 foot in diameter. What is the distance, in feet, between the centers of the two wheels?

A. \(\frac{15-\pi}{2}\)

B. \(\frac{5\pi}{4}\)

C. \(15-2\pi\)

D. \(15-\pi\)

E. \(2\pi\)

Attachment:
Conveyer Belt.jpg


Similar question to practice: as-shown-in-the-figure-above-a-thin-conveyor-belt-12-meters-160447.html
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As shown in the figure above, a thin conveyor belt 15 feet long is [#permalink]
Here's a visual on how I approached this question:

i.ibb.co/BTyvKNb/image.png (I can't post the image because I don't have more than 5 posts.)

This visual allows you to convey the image into an equation equal to 15 = 2(Length) + pi(d)/2 + pi(d)/2. Since in the stem we are given that d (diameter) is equal to 1 we can now solve for the length. 15 = 2(Length) + pi/2 + pi/2, then (15 - pi)/2 = length.
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Re: As shown in the figure above, a thin conveyor belt 15 feet long is [#permalink]
I have one doubt

As we Know that Circumference of the Circle is (Pie) and we know that belt is moving around Half of the Circle.
then we are not Calculating the half circumference of Circle which ((Pie/2)+1) 1 is dia of Circle
Bcz this is the formula of half circumference
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Re: As shown in the figure above, a thin conveyor belt 15 feet long is [#permalink]
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Solution:

Each wheel has a radius of 0.5 meters

=>Circumference of each wheel = 2 x π x 0.5 = π meters

Semi-perimeter of two circles covered by the belt = 2 x (π x 0.5) =π metres

The belt is 15 meters long

=> The two straight pieces of the belt measure (15 - π) metres together

=>Distance between the centers of the circles is (15 - π)/2 (option a)

Devmitra Sen
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Re: As shown in the figure above, a thin conveyor belt 15 feet long is [#permalink]
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Hi, I understand how the problem was solved, my only issue is that I did not assume the conveyor belt covered only half the circle because of the "Figure is not drawn to scale" note. Why was it okay to make that assumption while there's a note there, and what assumption would not be okay to make?
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Re: As shown in the figure above, a thin conveyor belt 15 feet long is [#permalink]
centuryotter wrote:
Hi, I understand how the problem was solved, my only issue is that I did not assume the conveyor belt covered only half the circle because of the "Figure is not drawn to scale" note. Why was it okay to make that assumption while there's a note there, and what assumption would not be okay to make?


I have the same question, ScottTargetTestPrep can you please help?
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Re: As shown in the figure above, a thin conveyor belt 15 feet long is [#permalink]
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yalembagrad wrote:
centuryotter wrote:
Hi, I understand how the problem was solved, my only issue is that I did not assume the conveyor belt covered only half the circle because of the "Figure is not drawn to scale" note. Why was it okay to make that assumption while there's a note there, and what assumption would not be okay to make?


I have the same question, ScottTargetTestPrep can you please help?


When a figure is not drawn to scale, it means that certain measures such as lengths, distances, angles etc. can be different from the way it is represented in the figure. For instance, in this question, the distance between the two centers appear to be roughly three times the length of the diameter of one circle, but an answer based on a visual estimate like this is not necessarily true when the figure is not drawn to scale. Indeed, the correct answer of (15 - π)/2 ≈ 5.9 is almost twice the visual estimate of 3. However, it is important to note that not everything in the figure should be dismissed as unreliable. In this case, the figure correctly depicts the top and bottom portions of the belt as being tangent to the two circles. Regardless of whether the figure is drawn to scale or not, this configuration ensures that the conveyor belt will cover exactly half of each circle.
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Re: As shown in the figure above, a thin conveyor belt 15 feet long is [#permalink]
CrackverbalGMAT wrote:
Solution:

Each wheel has a radius of 0.5 meters

=>Circumference of each wheel = 2 x π x 0.5 = π meters

Semi-perimeter of two circles covered by the belt = 2 x (π x 0.5) =π metres

The belt is 15 meters long

=> The two straight pieces of the belt measure (15 - π) metres together

=>Distance between the centers of the circles is (15 - π)/2 (option a)

Devmitra Sen
GMAT SME


Great explanation CrackverbalGMAT
Wondering why do we use circumference when question ask for distance between the two centre points? Why is not 2 x 0.5 =1metre here?
Could you kindly help clarify? Thanks
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