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Question from Challenge 6

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Praetorian
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Question from Challenge 6 [#permalink] New post   22 Feb 2006, 08:37
Thanks for answering the last question. Here one of three questions i am posting today. Please explain your answer choice.

What is the least possible value of x?

(1) x^2 - 5x + 5 = 1 - x
(2) x^2 = 4
(A) Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
(B) Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
(C) BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D) EACH statement ALONE is sufficient.
(E) Statements (1) and (2) TOGETHER are NOT sufficient.



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Re: Question from Challenge 6 [#permalink] New post   22 Feb 2006, 09:53
(1) x^2 - 5x + 5 = 1 - x

(x-2)^2=0

x=2 v x=-2

(2) x^2 = 4
x=2 v x=-2

both statements lead to x=-2 as the least possible value of x
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Re: Question from Challenge 6 [#permalink] New post   22 Feb 2006, 17:07
I believe D..
It is asking for least possible value.. and least possible value can be -2
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Re: Question from Challenge 6 [#permalink] New post   22 Feb 2006, 18:18
Agree with D.

What is the least possible value of x?

(1) x^2 - 5x + 5 = 1 - x
(2) x^2 = 4

i] x^2 - 5x + 5 = 1 - x
=> (x-2)^2=0
so x=2 ----suff

ii] x^2 = 4
=> (x-2)(x+2)=0
so x=-2,2 since -2 is smaller it is the least value here - suff
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Re: Question from Challenge 6 [#permalink] New post   22 Feb 2006, 18:32
good question, is not really testing math but how much you understand the tricks of the GMAT, I'll go with D as well
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Re: Question from Challenge 6 [#permalink] New post   22 Feb 2006, 21:25
1) (x-2)^2 = 0 => x= +- 2
2) x^2=4 =>x= +- 2

both are sufficient so answer is D

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Re: Question from Challenge 6 [#permalink] New post   22 Feb 2006, 21:39
Guys,
I too agree with D.
But, the least possible value from statement(1) is 2 (and not +/-2).
(x-2)^2 = 0 => x = 2 only.



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Re: Question from Challenge 6 [#permalink]
22 Feb 2006, 21:39
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