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Praetorian
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believe2
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Agree with D.

What is the least possible value of x?

(1) x^2 - 5x + 5 = 1 - x
(2) x^2 = 4

i] x^2 - 5x + 5 = 1 - x
=> (x-2)^2=0
so x=2 ----suff

ii] x^2 = 4
=> (x-2)(x+2)=0
so x=-2,2 since -2 is smaller it is the least value here - suff
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conocieur
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good question, is not really testing math but how much you understand the tricks of the GMAT, I'll go with D as well
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chiragr
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1) (x-2)^2 = 0 => x= +- 2
2) x^2=4 =>x= +- 2

both are sufficient so answer is D

Chirag
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chuckle
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Guys,
I too agree with D.
But, the least possible value from statement(1) is 2 (and not +/-2).
(x-2)^2 = 0 => x = 2 only.



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