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In May, Xiang sold 15 used cars. For these 15 cars, the

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In May, Xiang sold 15 used cars. For these 15 cars, the [#permalink] New post   17 Jul 2010, 11:18
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In May, Xiang sold 15 used cars. For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500. In June, Xiang sold 10 used cars. For these 10 cars, the range of the selling prices was $16,500 and the lowest selling price was $6,100. What was the range of the selling prices of the 25 used cars sold by Xiang in May and June?

1. $15,600
2. $15,750
3. $16,820
4. $18,100
5. $19,200
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Re: Problem Solving [#permalink] New post   17 Jul 2010, 16:33
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EnterMatrix wrote:
In May, Xiang sold 15 used cars. For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500. In June, Xiang sold 10 used cars. For these 10 cars, the range of the selling prices was $16,500 and the lowest selling price was $6,100. What was the range of the selling prices of the 25 used cars sold by Xiang in May and June?

1. $15,600
2. $15,750
3. $16,820
4. $18,100
5. $19,200


Edited the question as there was a typo.

Range = Highest Value - Lowest Value.

Range in May was 15,000 and the lowest price in May was 4,500, thus the highest price in May was 15,000+4,500=19,500.
Range in June was 16,500 and the lowest price in June was 6,100, thus the highest price in June was 16,500+6,100=22,600.

Lowest price of a car in May-June was 4,500 (May) and the highest price of a car in May-June was 22,600, thus the range for May-June is 22,600-4,500=18,100.

Answer: D.
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Re: Problem Solving [#permalink] New post   18 Jul 2010, 02:17
Cool...that works!
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Re: In May, Xiang sold 15 used cars. For these 15 cars, the [#permalink] New post   18 Sep 2016, 19:35
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Thank you for posting the solution although I am a bit confused. What is your reasoning for adding the selling price of the highest and lowest cars to get the highest price? They're the selling prices of 2 different cars. Why wouldn't the highest price just be... the highest price for each month? Thank you!
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Re: In May, Xiang sold 15 used cars. For these 15 cars, the [#permalink] New post   18 Sep 2016, 21:52
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Hyper1on89 wrote:
Thank you for posting the solution although I am a bit confused. What is your reasoning for adding the selling price of the highest and lowest cars to get the highest price? They're the selling prices of 2 different cars. Why wouldn't the highest price just be... the highest price for each month? Thank you!


For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500:

Range = Highest Value - Lowest Value.
15,000 = Highest Value - 4,500.
Highest Value = 15,000 + 4,500 = 19,500.
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Re: In May, Xiang sold 15 used cars. For these 15 cars, the [#permalink] New post   19 Sep 2016, 05:41
Quote:
For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500:

Range = Highest Value - Lowest Value.
15,000 = Highest Value - 4,500.
Highest Value = 15,000 + 4,500 = 19,500.


Thank you, Bunuel. Makes sense now.
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Re: In May, Xiang sold 15 used cars. For these 15 cars, the [#permalink] New post   25 Sep 2020, 14:07
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EnterMatrix wrote:
In May, Xiang sold 15 used cars. For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500. In June, Xiang sold 10 used cars. For these 10 cars, the range of the selling prices was $16,500 and the lowest selling price was $6,100. What was the range of the selling prices of the 25 used cars sold by Xiang in May and June?

1. $15,600
2. $15,750
3. $16,820
4. $18,100
5. $19,200

Solution:

The highest selling price of the cars sold in May was 4,500 + 15,000 = $19,500, and the highest selling price of the cars sold in June was 6,100 + 16,500 = $22,600. Therefore, the highest selling price of the cars sold in these two months was $22,600. Since the lowest selling price of the cars sold in the same two months was $4,500, the range was 22,600 - 4,500 = $18,100.

Answer: D
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Re: In May, Xiang sold 15 used cars. For these 15 cars, the [#permalink] New post   26 Nov 2020, 06:50
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A common enough question based on Range.

Range = Highest Value - Smallest Value

In the sum above, we know that the lowest value = Min(4500, 6100) = 4500

Largest Value = Range + Smallest Value

The largest Value = Max(15000 + 4500, 16500 + 6100) = Max(19500, 22600) = 22600

The range of the 25 cars = 22600 - 4500 = 18100


Option D

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Re: In May, Xiang sold 15 used cars. For these 15 cars, the [#permalink] New post   22 Aug 2023, 13:15
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Re: In May, Xiang sold 15 used cars. For these 15 cars, the [#permalink]
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