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In May, Xiang sold 15 used cars. For these 15 cars, the

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In May, Xiang sold 15 used cars. For these 15 cars, the  [#permalink]

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New post 17 Jul 2010, 10:18
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In May, Xiang sold 15 used cars. For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500. In June, Xiang sold 10 used cars. For these 10 cars, the range of the selling prices was $16,500 and the lowest selling price was $6,100. What was the range of the selling prices of the 25 used cars sold by Xiang in May and June?

1. $15,600
2. $15,750
3. $16,820
4. $18,100
5. $19,200
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Re: Problem Solving  [#permalink]

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New post 17 Jul 2010, 15:33
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EnterMatrix wrote:
In May, Xiang sold 15 used cars. For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500. In June, Xiang sold 10 used cars. For these 10 cars, the range of the selling prices was $16,500 and the lowest selling price was $6,100. What was the range of the selling prices of the 25 used cars sold by Xiang in May and June?

1. $15,600
2. $15,750
3. $16,820
4. $18,100
5. $19,200


Edited the question as there was a typo.

Range = Highest Value - Lowest Value.

Range in May was 15,000 and the lowest price in May was 4,500, thus the highest price in May was 15,000+4,500=19,500.
Range in June was 16,500 and the lowest price in June was 6,100, thus the highest price in June was 16,500+6,100=22,600.

Lowest price of a car in May-June was 4,500 (May) and the highest price of a car in May-June was 22,600, thus the range for May-June is 22,600-4,500=18,100.

Answer: D.
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Re: Problem Solving  [#permalink]

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New post 18 Jul 2010, 01:17
Cool...that works!
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Re: In May, Xiang sold 15 used cars. For these 15 cars, the  [#permalink]

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New post 18 Sep 2016, 18:35
Thank you for posting the solution although I am a bit confused. What is your reasoning for adding the selling price of the highest and lowest cars to get the highest price? They're the selling prices of 2 different cars. Why wouldn't the highest price just be... the highest price for each month? Thank you!
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Re: In May, Xiang sold 15 used cars. For these 15 cars, the  [#permalink]

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New post 18 Sep 2016, 20:52
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Hyper1on89 wrote:
Thank you for posting the solution although I am a bit confused. What is your reasoning for adding the selling price of the highest and lowest cars to get the highest price? They're the selling prices of 2 different cars. Why wouldn't the highest price just be... the highest price for each month? Thank you!


For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500:

Range = Highest Value - Lowest Value.
15,000 = Highest Value - 4,500.
Highest Value = 15,000 + 4,500 = 19,500.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: In May, Xiang sold 15 used cars. For these 15 cars, the  [#permalink]

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New post 19 Sep 2016, 04:41
Quote:
For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500:

Range = Highest Value - Lowest Value.
15,000 = Highest Value - 4,500.
Highest Value = 15,000 + 4,500 = 19,500.


Thank you, Bunuel. Makes sense now.
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Re: In May, Xiang sold 15 used cars. For these 15 cars, the  [#permalink]

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