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The figure above shows a construction plan for the intersect

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The figure above shows a construction plan for the intersect [#permalink] New post 17 Jan 2013, 05:33
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Attachment:
Roads.png
Roads.png [ 25.68 KiB | Viewed 3786 times ]
The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140
(2) s = 160
[Reveal] Spoiler: OA

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Last edited by Bunuel on 17 Jan 2013, 06:25, edited 1 time in total.
Edited the question.
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 17 Jan 2013, 06:05
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My net was lagging and wouldn't let me upload the image.
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 17 Jan 2013, 06:33
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Image
The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140. Not sufficient.
(2) s = 160. Not sufficient.

(1)+(2) Consider the width of the roads to be 0 as shown below:
Attachment:
Roads.png
Roads.png [ 14.39 KiB | Viewed 2147 times ]
From the figure we have that r+s+t=360 degrees --> 140+160+t=360 --> t=60 degrees. Sufficient.

Answer: C.
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 18 Jan 2013, 03:37
Seems a very basic question, but what other possible concepts are tested here? The official explanations was pretty convoluted had a parallelogram and all of that.
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 18 Jan 2013, 22:05
Bunuel wrote:
Image
The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140. Not sufficient.
(2) s = 160. Not sufficient.

(1)+(2) Consider the width of the roads to be 0 as shown below:
Attachment:
Roads.png
From the figure we have that r+s+t=360 degrees --> 140+160+t=360 --> t=60 degrees. Sufficient.

Answer: C.


Bunnel

I have small doubt here

Suppose the length is not 0 then you will have two variables and you cannot solve the equation i.e the equation becomes

Suppose width=X

Then T= 360-3X-R-S

and here you have 2 variables and 1 equation you cannot get a single solution

Am i right?
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 19 Jan 2013, 03:58
Expert's post
mydreammba wrote:
Bunuel wrote:
Image
The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140. Not sufficient.
(2) s = 160. Not sufficient.

(1)+(2) Consider the width of the roads to be 0 as shown below:
Attachment:
Roads.png
From the figure we have that r+s+t=360 degrees --> 140+160+t=360 --> t=60 degrees. Sufficient.

Answer: C.


Bunnel

I have small doubt here

Suppose the length is not 0 then you will have two variables and you cannot solve the equation i.e the equation becomes

Suppose width=X

Then T= 360-3X-R-S

and here you have 2 variables and 1 equation you cannot get a single solution

Am i right?


No you are not. The edges of the road are parallel, so there is 0 degree angle between them.
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PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: The figure above shows a construction plan for the intersect [#permalink] New post 19 Jan 2013, 06:57
Bunuel wrote:
mydreammba wrote:
Bunuel wrote:
Image
The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140. Not sufficient.
(2) s = 160. Not sufficient.

(1)+(2) Consider the width of the roads to be 0 as shown below:
Attachment:
Roads.png
From the figure we have that r+s+t=360 degrees --> 140+160+t=360 --> t=60 degrees. Sufficient.

Answer: C.


Bunnel

I have small doubt here

Suppose the length is not 0 then you will have two variables and you cannot solve the equation i.e the equation becomes

Suppose width=X

Then T= 360-3X-R-S

and here you have 2 variables and 1 equation you cannot get a single solution

Am i right?


No you are not. The edges of the road are parallel, so there is 0 degree angle between them.


Thanks Bunnel Got it
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 14 Feb 2013, 05:44
Quote:
(1)+(2) Consider the width of the roads to be 0 as shown below:


Bunuel - can you please elaborate it further ? why do we need to make this assumption ?

Regards.
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 14 Feb 2013, 07:19
Expert's post
anshunadir wrote:
Quote:
(1)+(2) Consider the width of the roads to be 0 as shown below:


Bunuel - can you please elaborate it further ? why do we need to make this assumption ?

Regards.


Go thru the file attached. Then you will understand the point which Bunuel is making.

Regards,

Abhijit
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parallel lines.docx [11.83 KiB]
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 25 Sep 2014, 05:25
Hi Guys,

I assumed Angle R = Angle S due to the parallel lines property. Hence for me each statement was sufficient. Why is R not equal to S?
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 25 Sep 2014, 20:48
piyusharma wrote:
Hi Guys,

I assumed Angle R = Angle S due to the parallel lines property. Hence for me each statement was sufficient. Why is R not equal to S?



Because the two parallel lines you considered are not cut by the same traversal. So angle R is not equal to angle S.
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Re: The figure above shows a construction plan for the intersect [#permalink] New post 25 Sep 2014, 21:55
Expert's post
piyusharma wrote:
Hi Guys,

I assumed Angle R = Angle S due to the parallel lines property. Hence for me each statement was sufficient. Why is R not equal to S?


Also note that in DS questions, the two statements never contradict each other. If you had assumed that angle R = angle S, the two statements should have told you that that is not true.
Statement 1 tells you that angle R is 140. According to you, then angle S should be 140 too. But statement 2 tells you that angle S is 160. This means there is something wrong in your assumption.
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Re: The figure above shows a construction plan for the intersect   [#permalink] 25 Sep 2014, 21:55
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