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The ratio between x and y is 7/9; x and y are increased by 4, what is [#permalink]
x and y can be 7 and 9 in that case 11/13 can be the answer.
It can also be 14 and 18 and so on and in that case the ratio would be 9/11.
It will have different values depending on the values for x and y.
So the answer is E
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Re: The ratio between x and y is 7/9; x and y are increased by 4, what is [#permalink]
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Bunuel wrote:
The ratio between x and y is 7/9; x and y are increased by 4, what is the ratio between the new values of x and y?

A) 7/9
B) 14/9
C) 7/18
D) 11/13
E) It Cannot Be Determined


We see that x : y = 7n : 9n

So x and y can be 7 and 9, 14 and 18, 21 and 27, etc.

Increasing both x and y by 4 will create a new ratio depending on the original values of x and y. Since we don’t know the actual original values of x and y, we cannot determine the new ratio.

Answer: E
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Re: The ratio between x and y is 7/9; x and y are increased by 4, what is [#permalink]
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Bunuel wrote:
The ratio between x and y is 7/9; x and y are increased by 4, what is the ratio between the new values of x and y?

A) 7/9
B) 14/9
C) 7/18
D) 11/13
E) It Cannot Be Determined


Let's test some possible values of x and y...

Given: The ratio of x to y is \(\frac{7}{9}\)

Case i: It could be the case that \(x = 7\) and \(y = 9\)
When we increase both values by \(4\), we get: \(\frac{7+4}{9+4}=\frac{11}{13}\)

Case ii: It could also be the case that \(x = 14\) and \(y = 18\)
When we increase both values by \(4\), we get: \(\frac{14+4}{18+4}=\frac{18}{22}=\frac{9}{11}\)

Answer: E
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Re: The ratio between x and y is 7/9; x and y are increased by 4, what is [#permalink]
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Re: The ratio between x and y is 7/9; x and y are increased by 4, what is [#permalink]
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