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Three children A, B and C have a toal of $1.20 among them.

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saurya_s
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Three children A, B and C have a toal of $1.20 among them. [#permalink] New post   07 Sep 2004, 16:35
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C
D
E

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Three children A, B and C have a toal of $1.20 among them. DOes C has the most money?
1 A has 35 cents
2 C has 40 cents



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Re: Three children A, B and C have a toal of $1.20 among them. [#permalink] New post   07 Sep 2004, 19:50
Seems like it's C. Is there any catch here?
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Re: Three children A, B and C have a toal of $1.20 among them. [#permalink] New post   07 Sep 2004, 21:46
Three children A, B and C have a toal of $1.20 among them. DOes C has the most money?
1 A has 35 cents
2 C has 40 cents

Paul, there is a catch here. The answer shd be B.

A is not sufficient because B or C may have more than 40 or both could have euall amount but each will have amount greater than 35

B is suffucent. because C has 40 and if the money is shared equally, everybody will have 40 and therefore we can say that C does not have the most money,
similarly if the money is not shared equally and C has 40,it means somebody could have more than 40 which would be greater than C's share and here again we can answer No to the question.
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Re: Three children A, B and C have a toal of $1.20 among them. [#permalink] New post   07 Sep 2004, 22:02
Yes, I've come across problems like this again and can't believe I fell into it... :arh
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Re: Three children A, B and C have a toal of $1.20 among them. [#permalink] New post   07 Sep 2004, 23:01
Another victim here :wall
I've answered fast and then I've spent some time to find the trap but it seems I didn't get it.
Very good problem. Could kill me If I get this at the begining of the real test because I will think that the first question will be a little easy s O am not sure I will take the extra time to check it so well
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Re: Three children A, B and C have a toal of $1.20 among them. [#permalink] New post   07 Sep 2004, 23:31
cant believe .... that i fell in to the trap
i have seen these kinda sums so many times !!
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Re: Three children A, B and C have a toal of $1.20 among them. [#permalink] New post   08 Sep 2004, 01:39
I fell as well, so I had posted. how does one go about this sort of problem?
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Re: Three children A, B and C have a toal of $1.20 among them. [#permalink] New post   08 Sep 2004, 10:12
There is no method known to go about such problems in Data sufficency.
All one has to do is to be extremely careful of equations that look so simple to solve when you you can combine the two statement.
under the simplicity are traps. The funny thing about such traps is that
ETS most often than not makes the first statement insufficient and the second part sufficient so that when you see statement one as insufficient, you are likely to also think that statement 2 is insufficient and thus the only solution can be found by combining the two statements.

I will be posting similar questions very soon on this forum. watch out for them .
I have classified then under the DANGEROUS TRAPS UNDER DATA SUFFICIENCY.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Thank you for understanding, and happy exploring!
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Re: Three children A, B and C have a toal of $1.20 among them. [#permalink]
08 Sep 2004, 10:12
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