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i know after seeing the solution u would say this question is a cake walk..but i have one confusion please help me wid it..

acc to GMAT , the figure is to scale, now can i assume this graph as a parabola ?? coz it looks to be a one...if it does then it can complicate the problem ....

on the graph above, when x = 1/2, y = 2; and x =1,y=1. The graph is symmetric with repsect to the vertical linke at x = 2. According to the graph, when x = 3, y = ?

i know this is a longer method..no doubt..but why doesn't it give the same answer...can anyone please explain it...

You can't assume the graph to be a parabola because it isn't one. And
even if it were: the y-value for x= 1/2 is only given to confuse us, so
don't use a formula and take the y-value for x=1 .

but i think i found my mistake this curve may be a fourth degree , sixth degree or any equation with even powers of X , since that is not clear so we cannot take it to be a "quadratic" equation.