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Re: What is the number of integers from 1 to 1000... [#permalink]
12 Feb 2009, 22:49

14

This post received KUDOS

What is the number of integers from 1 to 1000 (inclusive) that are not divisible by 11 nor by 35?

* 884 * 890 * 892 * 910 * 945 --------------------------------- We can go this way:

Calculate the no. of terms from 1 to 1000 (inclusive) that are divisible by 11 or 35 or both.

1.) Total no. of terms divisible by 11 are 90. We can calculate this by finding the first and last terms, which are 11 & 990 respectively. Then we will find the total no. of terms by using equation

Last Term = a + (n-1)d where a=11, d=11, Last Term=990.

So, n=90

2.) Similarly, total no. of terms divisible by 35 are 28. Find it using the above method.

3.) To find terms divisible by both 11 & 35, find the first term. Since both have no common factors except 1, just multiply 11 & 35 to get the first common term i.e., 385. Next term is 770.

So, in total, there are 2 common terms for 11 & 35. ------------------------------

Hence, the total no. of terms from 1 to 1000 (inclusive) that are divisible by 11 or 35 or both = 90 + 28 - 2 = 116

So, the correct answer = 1000 - 116 = 884, which will give us the total no. of terms that are divisible neither by 11 nor 35.

So, I'll go for first option, i.e., 884

Though the explanation looks a bit lengthy, it'll not take much time to solve.

HTH
_________________

+++ Believe me, it doesn't take much of an effort to underline SC questions. Just try it out. +++ +++ Please tell me why other options are wrong. +++

~~~ The only way to get smarter is to play a smarter opponent. ~~~

Last edited by Technext on 13 Feb 2009, 02:13, edited 3 times in total.

# of multiples of 11 in the given range (last-first)/multiple+1=(990-11)/11+1=90 (check this: totally-basic-94862.html); # of multiples of 35 in the given range (last-first)/multiple+1=(980-35)/35+1=28; # of multiples of both 11 and 35 is 2 (11*35=385 and 770);

So, # of multiples of 11 or 35 in the given range is 90+28-2=116. Thus numbers which are not divisible by either of them is 1000-116=884.

Re: What is the number of integers from 1 to 1000 (m07q14) [#permalink]
09 Apr 2012, 21:19

2

This post received KUDOS

Hello,

Calculate the no. of terms from 1 to 1000 (inclusive) that are divisible by 11 or 35 or both.

1. No of terms divisible by 11 -> 1000/11 = 90 2. No of terms divisible by 35 -> 1000/35 = 28 3. No of terms divisible by 11 and 35 -> 1000/(11*35) = 2

Re: What is the number of integers from 1 to 1000... [#permalink]
09 Apr 2013, 05:28

x2suresh wrote:

xALIx wrote:

What is the number of integers from 1 to 1000 (inclusive) that are not divisible by 11 nor by 35?

* 884 * 890 * 892 * 910 * 945

1000/11 = 90.xx divisible 11 = 90

1000/35 = 28.x Divisible by 35 = 28

We need to exclude 11*35 and 2*11*35 numbers are counted twice.

Anser = 1000-(90+28-2) =1000-116=884

That's what was going on in my mind, but I missed out because of a lack of clarity in understanding "neither 11 nor 35" & double counted the common ones...

Thank you for completing the simple effective analysis!
_________________

Re: What is the number of integers from 1 to 1000 (m07q14) [#permalink]
09 Apr 2013, 07:48

In order to find the count of numbers between 1 and 1000 that are divisible by neither 11 nor 35, first find the count of numbers that are divisible by either of the numbers, then subtract that number from 1000 to get to the answer.

To find the count of the numbers that are divisible by either of the numbers, find the count of positive multiples of 11, that of 35, and that of 11*35 in the given range. Then add the first two counts; subtract the third count. Then, subtract this number from 1000 to get to the answer.

Count of multiple of 11 less than 1000: 11.x < 1000 => x < 1000/11 => x < 90.9 Therefore, the count of positive numbers less than 1000 and divisible by 11 is 90.

Count of multiple of 35 less than 1000: 35.y < 1000 => y < 1000/35 => y < 28.5 Therefore, the count of positive numbers less than 1000 and divisible by 35 is 28.

Count of multiple of 11*35 less than 1000: 11.35.z < 1000 => z < 1000/35*11 => z < 2.5 Therefore, the count of positive numbers less than 1000 and divisible by 11*35 is 2.

Count of the positive number less than 1000 and divisible by either of the numbers = 90 + 28 - 2 = 116

So, the count of the numbers between 1 and 1000 that are divisible by neither 11 nor 35 = 1000 - 116 = 884

Correct answer is A.

gmatclubot

Re: What is the number of integers from 1 to 1000 (m07q14)
[#permalink]
09 Apr 2013, 07:48