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A pet store holds cats and dogs. If the difference between [#permalink]
 16 Aug 2003, 05:56
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1. A pet store holds cats and dogs. If the difference between the number of cats and the number of dogs is 13. What could be the ratio of Cats to dogs in the pet store?
a. 1:3 b. 1:4 c. 1:5 d. 2:5 e. 4:5
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e?
we have c cats and d dogs... d=c+13... so our ratio is c/d=c/(c+13)... if we plug every answer (not very elegant, i admit it), we see that the only way to get an integer for c is 4/5
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stolyar, how did you get e? did you not plug numbers?
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SVP
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Did plug numbers, but started from E 
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yes E. 4:5 is the correct answer.
the difference between the number of cats and dogs must be divisible by difference between the numbers that represent both animals in ratio. Since 13 is a prime number , it is only divisible by 1 and 13 .Therefore, the correct choice is the one where the difference between the numbers is 1.
Regards,
Ara
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Maybe I am missing something, but my approach is quite simpler.
As the difference between cats and dogs is 13, there are more cats than dogs. This make E the only possible solution, as all the others make more dogs than cats.
???????
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