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Re: An escalator is descending at constant speed. A walks down and takes 5 [#permalink]
chetansharma Could you please help with this one ? Im not getting the logic of this question. Please help with a detailed solution.


Best !!!
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Re: An escalator is descending at constant speed. A walks down and takes 5 [#permalink]
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Steps travelled by A = Steps travelled by B

50+ 5*x = 90 + x (as B takes 5 times less time)
So, 4*x= 40, x= 10
Total steps = 90 +10 = 100

I think C. :)
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Re: An escalator is descending at constant speed. A walks down and takes 5 [#permalink]
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Bunuel wrote:
An escalator is descending at constant speed. A walks down and takes 50 steps to reach the bottom. B runs down and takes 90 steps in the same time as A takes 10 steps. How many steps are visible when the escalator is not operating?

A. 90
B. 95
C. 100
D. 105
E. 150



ShankSouljaBoi, the question misses out on mentioning that B has reached the bottom in 90steps. It just mentions that B takes 90 steps in the time A takes 10 steps. And that is a big issue!

So, say the question meant that B reaches the bottom in 90 steps, and in the same time as A takes 10 steps. Since A takes 50 steps to reach bottom and the speed of escalator is constant, we can say A will take 1/5 of total time to take 10 steps. This further means that B reaches the bottom in 1/5 th time taken by A.

Now let the speed of escalator be such that it covers x steps in the time A takes 10 steps, so in terms of B the number of steps = 90+x, while in terms of A, the number of steps = \(50+(\frac{50}{10})*x=50+5x\)
=> \(90+x=50+5x....x=10\)
steps = 90+10=100

C
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Re: An escalator is descending at constant speed. A walks down and takes 5 [#permalink]
chetansharma wrote:
Bunuel wrote:
An escalator is descending at constant speed. A walks down and takes 50 steps to reach the bottom. B runs down and takes 90 steps in the same time as A takes 10 steps. How many steps are visible when the escalator is not operating?

A. 90
B. 95
C. 100
D. 105
E. 150



ShankSouljaBoi, the question misses out on mentioning that B has reached the bottom in 90steps. It just mentions that B takes 90 steps in the time A takes 10 steps. And that is a big issue!

So, say the question meant that B reaches the bottom in 90 steps, and in the same time as A takes 10 steps. Since A takes 50 steps to reach bottom and the speed of escalator is constant, we can say A will take 1/5 of total time to take 10 steps. This further means that B reaches the bottom in 1/5 th time taken by A.

Now let the speed of escalator be such that it covers x steps in the time A takes 10 steps, so in terms of B the number of steps = 90+x, while in terms of A, the number of steps = \(50+(\frac{50}{10})*x=50+5x\)
=> \(90+x=50+5x....x=10\)
steps = 90+10=100

C


That's why I cdnt form the equation. So crystal clear now thank you so much chetansharma :)

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Re: An escalator is descending at constant speed. A walks down and takes 5 [#permalink]
I don't get the 1/5 ratio here - can someone explain please?
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Re: An escalator is descending at constant speed. A walks down and takes 5 [#permalink]
azamatboden wrote:
I don't get the 1/5 ratio here - can someone explain please?




Hi
The following explanation might help those with the quoted doubt.

So, A is known to take 10 steps when B takes 90 steps. Lets assume this happens at a time t.
i.e, A takes 1 step in t/10 seconds.
so, A takes its 50 steps in (50t)/10=5t seconds.
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Re: An escalator is descending at constant speed. A walks down and takes 5 [#permalink]
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