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Country A has 80 airports (must be a wealthy country!). The
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10 Feb 2007, 04:39
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Country A has 80 airports (must be a wealthy country!). The distances between any two airports are not the same. Every airplane taking off from an airport flies to the nearest airport. All of the following can be the number of airplanes arriving at any airport, EXCEPT:
A. 2
B. 3
C. 4
D. 5
E. 6
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Re: Country A has 80 airports (must be a wealthy country!). The
[#permalink]
10 Feb 2007, 07:43
laxieqv wrote:
Country A has 80 airports (must be a wealthy country!). The distances between any two airports are not the same. Every airplane taking off from an airport flies to the nearest airport. All of the following can be the number of airplanes arriving at any airport, EXCEPT:
A. 2 B. 3 C. 4 D. 5 E. 6
Interesting question.
I am not really sure how to deal with this question. But, it may relate to the hexagonal network that all the distances between spot are the same. The number of airplanes arriving at any airport will be 6.
If the distance is not the same, 6 is impossible. So the answer is E?
Re: Country A has 80 airports (must be a wealthy country!). The
[#permalink]
10 Feb 2007, 09:49
laxieqv wrote:
Country A has 80 airports (must be a wealthy country!). The distances between any two airports are not the same. Every airplane taking off from an airport flies to the nearest airport. All of the following can be the number of airplanes arriving at any airport, EXCEPT:
A. 2 B. 3 C. 4 D. 5 E. 6
go with E. since the distance between two airports are not the same, the maximum number of airports that can be equidistance in a circular way is 6, which is not possible. therefore, it is 6.
Re: Country A has 80 airports (must be a wealthy country!). The
[#permalink]
10 Feb 2007, 13:00
amorpheus wrote:
devilmirror wrote:
laxieqv wrote:
Country A has 80 airports (must be a wealthy country!). The distances between any two airports are not the same. Every airplane taking off from an airport flies to the nearest airport. All of the following can be the number of airplanes arriving at any airport, EXCEPT:
A. 2 B. 3 C. 4 D. 5 E. 6
Interesting question.
I am not really sure how to deal with this question. But, it may relate to the hexagonal network that all the distances between spot are the same. The number of airplanes arriving at any airport will be 6.
If the distance is not the same, 6 is impossible. So the answer is E?
Why hexagonal only why not octagonal?
Draw 2 circles. The first circle has a regular hexagon inside. The other has a regular octagonal.
In the first circle, the distance of each side of hexagon is equal to radius of the circle.
In the second circle, the distance of each side of octagonal is shorter than the radius.
On my assumption, I try to find a picture that every dot on the network must have the same distance. Only hexagonal shape can create such condition.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
gmatclubot
Re: Country A has 80 airports (must be a wealthy country!). The [#permalink]