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10 Feb 2007, 04:39
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Country A has 80 airports (must be a wealthy country!). The distances between any two airports are not the same. Every airplane taking off from an airport flies to the nearest airport. All of the following can be the number of airplanes arriving at any airport, EXCEPT:
A. 2
B. 3
C. 4
D. 5
E. 6
A. 2
B. 3
C. 4
D. 5
E. 6
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10 Feb 2007, 07:43
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laxieqv
Interesting question.
I am not really sure how to deal with this question. But, it may relate to the hexagonal network that all the distances between spot are the same. The number of airplanes arriving at any airport will be 6.
If the distance is not the same, 6 is impossible. So the answer is E?
10 Feb 2007, 09:49
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laxieqv
go with E. since the distance between two airports are not the same, the maximum number of airports that can be equidistance in a circular way is 6, which is not possible. therefore, it is 6.
