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# Given A and B are non negative, is A5 > B2

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Joined: 11 Apr 2012
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Given A and B are non negative, is A5 > B2 [#permalink]

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26 Aug 2012, 18:31
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Given $$A$$ and $$B$$ are non negative, is $$A^5 > B^2$$?

(1) $$A^\frac{1}{3} > B^2$$

(2) $$A > B^2$$
[Reveal] Spoiler: OA

Last edited by Harley1980 on 22 Apr 2015, 13:46, edited 2 times in total.
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Re: Given A and B are non negative, is A5 > B2 [#permalink]

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26 Aug 2012, 19:00
2
KUDOS
(1) A = 1 and B = 1/2

A^5 > B^2

A = 1/2 and B = 1/2

A^5 < B^2

(1) is insufficient

(B) Again let A = 1/3 B = 1/3

A > B^2

But A^5 < B^2

A = 1 B = 1/2

A > B^2

but A^5 > B^2

(A) and (B) together are insufficient

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Re: Given A and B are non negative, is A5 > B2 [#permalink]

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26 Aug 2012, 22:32
my approach:
from the question stem: 1. a and b is positive or zero.
we have to find whether a is a/ b are fractions.
Stem 1: not sufficient to decide. as if a is an positive integer then a^5 > B^2 BUT if is a fraction a^5 is not > B^2.
Stem 2: not sufficient for same reason.
Combining these to we can not decide whether a is a fraction or integer. we only can say a^1/3 and a are greater than B^2.
Any comparison between a^2 and a or any power of a would give a hints to solve the question.

E is the pick.
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Re: Given A and B are non negative, is A5 > B2 [#permalink]

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11 May 2013, 22:48
G800 wrote:
my approach:
from the question stem: 1. a and b is positive or zero.
we have to find whether a is a/ b are fractions.
Stem 1: not sufficient to decide. as if a is an positive integer then a^5 > B^2 BUT if is a fraction a^5 is not > B^2.
Stem 2: not sufficient for same reason.
Combining these to we can not decide whether a is a fraction or integer. we only can say a^1/3 and a are greater than B^2.
Any comparison between a^2 and a or any power of a would give a hints to solve the question.

E is the pick.

I dont understand how do we know that A and B are less than 0
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Re: Given A and B are non negative, is A5 > B2 [#permalink]

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12 May 2013, 02:53
rahul18 wrote:
G800 wrote:
my approach:
from the question stem: 1. a and b is positive or zero.
we have to find whether a is a/ b are fractions.
Stem 1: not sufficient to decide. as if a is an positive integer then a^5 > B^2 BUT if is a fraction a^5 is not > B^2.
Stem 2: not sufficient for same reason.
Combining these to we can not decide whether a is a fraction or integer. we only can say a^1/3 and a are greater than B^2.
Any comparison between a^2 and a or any power of a would give a hints to solve the question.

E is the pick.

I dont understand how do we know that A and B are less than 0

A and B are not less than zero. The stem says that "A and B are non negative", so each is 0 or positive.
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Re: Given A and B are non negative, is A5 > B2 [#permalink]

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13 May 2013, 11:40
Insufficient even by both statements

Ans E. See attached image for calcs.
Attachments

Acube_Bsquare.JPG [ 43.63 KiB | Viewed 1802 times ]

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Re: Given A and B are non negative, is A5 > B2 [#permalink]

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22 Apr 2015, 13:21
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Re: Given A and B are non negative, is A5 > B2   [#permalink] 22 Apr 2015, 13:21
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# Given A and B are non negative, is A5 > B2

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