Find all School-related info fast with the new School-Specific MBA Forum

It is currently 23 Oct 2014, 23:18

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

How many integers from 0 to 50, inclusive, have a remainder

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Director
Director
avatar
Joined: 09 Aug 2006
Posts: 767
Followers: 1

Kudos [?]: 52 [0], given: 0

How many integers from 0 to 50, inclusive, have a remainder [#permalink] New post 27 Jun 2007, 03:00
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3?

A.14
B.15.
C.16
D.17
E.18

Pls. explain your solution.
Senior Manager
Senior Manager
avatar
Joined: 04 Jun 2007
Posts: 349
Followers: 1

Kudos [?]: 14 [0], given: 0

Re: PS: Remainder when Divided by 3 [#permalink] New post 27 Jun 2007, 04:26
GK_Gmat wrote:
How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3?

A.14
B.15.
C.16
D.17
E.18

Pls. explain your solution.


Between 0 and 50 (inclusive) the first and last numbers satisfying the given conditions are 1 and 49. Therefore, all other numbers, along with these will form an arithmetic progression with common difference 3.
So, we have: 49 = 1 + (n-1)*3 which gives n=17.
Hence, D.
CIO
CIO
User avatar
Joined: 09 Mar 2003
Posts: 466
Followers: 1

Kudos [?]: 28 [0], given: 0

Re: PS: Remainder when Divided by 3 [#permalink] New post 27 Jun 2007, 05:08
GK_Gmat wrote:
How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3?

A.14
B.15.
C.16
D.17
E.18

Pls. explain your solution.


I get the same answer, but i use a different method. When we have a list of consecutive numbers and we want to count the numbers, it's always:

Subtract
Divide (by d)
Add 1

So the list goes from 1 to 49:

Subtract: 49 - 1 = 48
Divide by d: 48/3 = 16
Add 1: 16 + 1 = 17

I just find it's easier for students to remember that method than to remember a formula.

Humble opinion.
Director
Director
avatar
Joined: 06 Sep 2006
Posts: 746
Followers: 1

Kudos [?]: 15 [0], given: 0

 [#permalink] New post 27 Jun 2007, 08:23
(48 - 0)/3 + 1
17
D.

No. of term b/w consecutive numbers = (Last - First)/Difference + 1

Difference is 1 for sequence like 1,2, 3,...
Difference is 2 for odd/even
Director
Director
avatar
Joined: 01 May 2007
Posts: 795
Followers: 1

Kudos [?]: 79 [0], given: 0

 [#permalink] New post 11 Nov 2007, 15:10
I solved this the following way... does this make sense?

51 = 3q + 1

q = 16.6667 or round to 17.

I got 51 by getting 50-0 plus one (since we said zero to 50 inclusive.)
Director
Director
User avatar
Joined: 13 Dec 2006
Posts: 521
Location: Indonesia
Followers: 6

Kudos [?]: 96 [0], given: 0

 [#permalink] New post 11 Nov 2007, 16:58
Hi,

guys why am I getting 16 instead of 17, as you have got....

In my opinion the first number between 0 to 50, which will give remainder of 1 when divided by 3 is 4. and the last number is 49.

in other words 16* 3 = 48, add one to 48 will give 49. which will be the last number.

so answer should be 16... let me know, where am I wrong? My answer is C=16

Amardeep
Director
Director
User avatar
Joined: 08 Jun 2007
Posts: 583
Followers: 2

Kudos [?]: 72 [0], given: 0

 [#permalink] New post 11 Nov 2007, 17:09
Amardeep Sharma wrote:
Hi,

guys why am I getting 16 instead of 17, as you have got....

In my opinion the first number between 0 to 50, which will give remainder of 1 when divided by 3 is 4. and the last number is 49.

in other words 16* 3 = 48, add one to 48 will give 49. which will be the last number.

so answer should be 16... let me know, where am I wrong? My answer is C=16

Amardeep


The first number should be 1 . Remember 0 is multiple of all numbers.
3*0 + 1 = 1
  [#permalink] 11 Nov 2007, 17:09
    Similar topics Author Replies Last post
Similar
Topics:
18 Experts publish their posts in the topic How many integers from 0 to 50, inclusive, have a remainder Economist 22 24 Mar 2009, 22:51
How many integers from 0 to 50, inclusive, have a remainder haichao 2 11 Nov 2008, 19:29
How many integers from 0 to 50 inclusive have a remainder of puma 14 12 May 2008, 07:46
How many integers from 0 to 50, inclusive, have a remainder M8 7 30 Apr 2006, 07:05
How many integers from 0 to 50, inclusive, have a remainder vivek123 16 28 Jan 2006, 10:20
Display posts from previous: Sort by

How many integers from 0 to 50, inclusive, have a remainder

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.