|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
17 Dec 2009, 02:41
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
73% (00:58) correct
27%
(01:06)
wrong
based on 361
sessions
History
Date
Time
Result
Not Attempted Yet
How many integers from 0-50 have a remainder of 3 when divided by 9?
A. 5
B. 6
C. 7
D. 8
E. 9
A. 5
B. 6
C. 7
D. 8
E. 9
17 Dec 2009, 03:13
Kudos
Bookmarks
zaarathelab
A remainder of 3 when divided by 9 --> \(n=9q+3\), where q is an integer \(\geq{0}\).
\(9q+3<50\) --> \(q<5\frac{2}{9}\), hence q can take 6 values from 0 to \(5\).
Answer: B (6).
Or, one can just manually list the numbers of the form \(n=9q+3\), which are less than 50: 3, 12, 21, 30, 39, and 48. Total of 6 numbers.
General Discussion
17 Dec 2009, 02:55
Kudos
Bookmarks
All numbers should be of the form 9c+3 where c is a constant.
Min is 3 for c=0
Max in 48 for c=5
The answer should be B = 6
Min is 3 for c=0
Max in 48 for c=5
The answer should be B = 6
