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Re: PS: Remainder when Divided by 3 [#permalink]
27 Jun 2007, 04:26

GK_Gmat wrote:

How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3?

A.14 B.15. C.16 D.17 E.18

Pls. explain your solution.

Between 0 and 50 (inclusive) the first and last numbers satisfying the given conditions are 1 and 49. Therefore, all other numbers, along with these will form an arithmetic progression with common difference 3.
So, we have: 49 = 1 + (n-1)*3 which gives n=17.
Hence, D.