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If a code word is defined to be a sequence of different

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SVP
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If a code word is defined to be a sequence of different [#permalink] New post 14 Apr 2008, 12:09
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A
B
C
D
E

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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
If a code word is defined to be a sequence of different letters chosen from the 10 letters A,B,C,D,E,F,G,H,I, and J, what is the ratio of the number of 5-letter code words to the number of 4-letter code words?

a) 5 to 4
b) 3 to 2
c) 2 to 1
d) 5 to 1
e) 6 to 1



Would someone please show me how to solve this problem?
thanks
Director
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Re: PS: Ratios [#permalink] New post 14 Apr 2008, 12:28
Possibilities for 5 letter word = 10*9*8*7*6 (First letter can any one of 10, next can anyone of remaining 9, and so on)
Possibilities for 4 letter word = 10*9*8*7

Ratio = 10*9*8*7*6/10*9*8*7 = 6/1

Answer E.
Senior Manager
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Re: PS: Ratios [#permalink] New post 14 Apr 2008, 16:27
That was cool Abhijit.

I got the answer different way that is more convoluted in a way

I did it like this

Number of ways = (5! * 10C5)/(4! * 10C4)
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Re: PS: Ratios [#permalink] New post 14 Apr 2008, 16:30
do we assume no repitition here ?
Director
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Re: PS: Ratios [#permalink] New post 14 Apr 2008, 17:07
pmenon wrote:
do we assume no repitition here ?

Repetition is always mentioned in the question, by default assume all questions to be non-repetition cases.
Re: PS: Ratios   [#permalink] 14 Apr 2008, 17:07
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