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If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho [#permalink]
21 Mar 2012, 08:04

2

This post received KUDOS

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

47% (02:12) correct
52% (01:19) wrong based on 208 sessions

If t = 1/(2^9*5^3) is expressed as a terminating decimal, how many zeros will t have between the decimal point and the fist nonzero digit to the right of the decimal point?

If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?

A. Three B. Four C. Five D. Six E. Nine

bunnel , can you please explain this problem

Given: t=\frac{1}{2^9*5^3}.

Multiply by \frac{5^6}{5^6} --> t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625. Hence t will have 4 zerose between the decimal point and the fist nonzero digit.

Answer: B.

Or another way t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}.

Now, \frac{1}{64,000} is greater than \frac{1}{100,000}=0.00001 and less than \frac{1}{10,000}=0.0001, so \frac{1}{64,000} is something like 0.0000xxxx.

If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?

A. Three B. Four C. Five D. Six E. Nine

bunnel , can you please explain this problem

Given: t=\frac{1}{2^9*5^3}.

Multiply by \frac{5^6}{5^6} --> t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625. Hence t will have 4 zerose between the decimal point and the fist nonzero digit.

Answer: B.

Or another way t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}.

Now, \frac{1}{64,000} is greater than \frac{1}{100,000}=0.00001 and less than \frac{1}{10,000}=0.0001, so \frac{1}{64,000} is something like 0.0000xxxx.

Answer: B.

Can someone please explain how is multiplying 5^6 to the denominator (2^9 * 5^3) get 10^9?

If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?

A. Three B. Four C. Five D. Six E. Nine

bunnel , can you please explain this problem

Given: t=\frac{1}{2^9*5^3}.

Multiply by \frac{5^6}{5^6} --> t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625. Hence t will have 4 zerose between the decimal point and the fist nonzero digit.

Answer: B.

Or another way t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}.

Now, \frac{1}{64,000} is greater than \frac{1}{100,000}=0.00001 and less than \frac{1}{10,000}=0.0001, so \frac{1}{64,000} is something like 0.0000xxxx.

Answer: B.

Can someone please explain how is multiplying 5^6 to the denominator (2^9 * 5^3) get 10^9?

If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?

A. Three B. Four C. Five D. Six E. Nine

bunnel , can you please explain this problem

Given: t=\frac{1}{2^9*5^3}.

Multiply by \frac{5^6}{5^6} --> t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625. Hence t will have 4 zerose between the decimal point and the fist nonzero digit.

Answer: B.

Or another way t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}.

Now, \frac{1}{64,000} is greater than \frac{1}{100,000}=0.00001 and less than \frac{1}{10,000}=0.0001, so \frac{1}{64,000} is something like 0.0000xxxx.

Answer: B.

1st method is really awasome to follow...thanks Bunuel
_________________

Regards, Harsha

Note: Give me kudos if my approach is right , else help me understand where i am missing.. I want to bell the GMAT Cat

Re: Terminating decimal OG [#permalink]
20 Oct 2012, 01:58

With a question like this always try to convert the numbers to 10^(x) times something so that you can see the shift of the decimal point. As stated above, the answer is B.
_________________

Hi, I still dont understand why we have to multiply by 5^6/5^6 i understand that this equals one but what is the general rule for this? how did you know to pick 5^6?

Thanks

Bunuel wrote:

TomB wrote:

If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?

A. Three B. Four C. Five D. Six E. Nine

bunnel , can you please explain this problem

Given: t=\frac{1}{2^9*5^3}.

Multiply by \frac{5^6}{5^6} --> t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625. Hence t will have 4 zerose between the decimal point and the fist nonzero digit.

Answer: B.

Or another way t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}.

Now, \frac{1}{64,000} is greater than \frac{1}{100,000}=0.00001 and less than \frac{1}{10,000}=0.0001, so \frac{1}{64,000} is something like 0.0000xxxx.

Hi, I still dont understand why we have to multiply by 5^6/5^6 i understand that this equals one but what is the general rule for this? how did you know to pick 5^6?

Thanks

Bunuel wrote:

TomB wrote:

If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?

A. Three B. Four C. Five D. Six E. Nine

bunnel , can you please explain this problem

Given: t=\frac{1}{2^9*5^3}.

Multiply by \frac{5^6}{5^6} --> t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625. Hence t will have 4 zerose between the decimal point and the fist nonzero digit.

Answer: B.

Or another way t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}.

Now, \frac{1}{64,000} is greater than \frac{1}{100,000}=0.00001 and less than \frac{1}{10,000}=0.0001, so \frac{1}{64,000} is something like 0.0000xxxx.

Answer: B.

Welcome to GMAT Club shahir16.

We want the denominator of the fraction to be written as some power of 10. We need that in order to transform the fraction into decimal easily.

Now, the denominator = 2^9 * 5^3, hence we need to multiply it by 5^6 to get 10^9.

Can you please show me step-by-step how to convert 2^9 * 5^3 to a power of 10? I am unclear on the concept of converting an expression with exponents to a power of 10. I appreciate your help

Answer: B.[/quote][/quote]

Welcome to GMAT Club shahir16.

We want the denominator of the fraction to be written as some power of 10. We need that in order to transform the fraction into decimal easily.

Now, the denominator = 2^9 * 5^3, hence we need to multiply it by 5^6 to get 10^9.

Can you please show me step-by-step how to convert 2^9 * 5^3 to a power of 10? I am unclear on the concept of converting an expression with exponents to a power of 10. I appreciate your help

Here it goes: (2^9 * 5^3)*5^6=2^9 * (5^3*5^6)=2^9*5^9=(2*5)^9=10^9.
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If t = 1/[(2^9)*(5^3)] is expressed as a terminating decima [#permalink]
23 Jun 2013, 00:54

If t = 1/[(2^9)*(5^3)] is expressed as a terminating decimal, how many zeros will t have between the decimal point and the fi rst nonzero digit to the right of the decimal point? (A) Three (B) Four (C) Five (D) Six (E) Nine
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Re: If t = 1/[(2^9)*(5^3)] is expressed as a terminating decima [#permalink]
23 Jun 2013, 01:00

Expert's post

sam15000 wrote:

If t = 1/[(2^9)*(5^3)] is expressed as a terminating decimal, how many zeros will t have between the decimal point and the fi rst nonzero digit to the right of the decimal point? (A) Three (B) Four (C) Five (D) Six (E) Nine

Merging similar topics. Please refer to the solutions above.
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