December 20, 2018 December 20, 2018 10:00 PM PST 11:00 PM PST This is the most inexpensive and attractive price in the market. Get the course now! December 22, 2018 December 22, 2018 07:00 AM PST 09:00 AM PST Attend this webinar to learn how to leverage Meaning and Logic to solve the most challenging Sentence Correction Questions.
Author 
Message 
TAGS:

Hide Tags

Senior Manager
Joined: 18 Sep 2009
Posts: 283

If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
21 Mar 2012, 08:04
Question Stats:
53% (01:46) correct 47% (01:42) wrong based on 1769 sessions
HideShow timer Statistics
If \(t = \frac{1}{(2^9*5^3)}\) is expressed as a terminating decimal, how many zeros will t have between the decimal point and the fist nonzero digit to the right of the decimal point? A. Three B. Four C. Five D. Six E. Nine
Official Answer and Stats are available only to registered users. Register/ Login.




Math Expert
Joined: 02 Sep 2009
Posts: 51307

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
21 Mar 2012, 09:46
TomB wrote: If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?
A. Three B. Four C. Five D. Six E. Nine
bunnel , can you please explain this problem Given: \(t=\frac{1}{2^9*5^3}\). Multiply by \(\frac{5^6}{5^6}\) > \(t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625\). Hence \(t\) will have 4 zerose between the decimal point and the fist nonzero digit. Answer: B. Or another way \(t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}\). Now, \(\frac{1}{64,000}\) is greater than \(\frac{1}{100,000}=0.00001\) and less than \(\frac{1}{10,000}=0.0001\), so \(\frac{1}{64,000}\) is something like \(0.0000xxxx\). Answer: B.
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics




Manager
Joined: 12 Mar 2012
Posts: 244
Concentration: Operations, Strategy

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
15 Apr 2012, 18:50
catty2004 wrote: Bunuel wrote: TomB wrote: If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?
A. Three B. Four C. Five D. Six E. Nine
bunnel , can you please explain this problem Given: \(t=\frac{1}{2^9*5^3}\). Multiply by \(\frac{5^6}{5^6}\) > \(t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625\). Hence \(t\) will have 4 zerose between the decimal point and the fist nonzero digit. Answer: B. Or another way \(t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}\). Now, \(\frac{1}{64,000}\) is greater than \(\frac{1}{100,000}=0.00001\) and less than \(\frac{1}{10,000}=0.0001\), so \(\frac{1}{64,000}\) is something like \(0.0000xxxx\). Answer: B. Can someone please explain how is multiplying 5^6 to the denominator (2^9 * 5^3) get 10^9? 5^6*(2^9*5^3) = 2^9*5^(6+3)= 2^9 *5^9 = (2*5)^9 = 10^9 Hope this helps...!!!
_________________
Practice Practice and practice...!!
If my reply /analysis is helpful>please press KUDOS If there's a loophole in my analysis> suggest measures to make it airtight.




Manager
Joined: 09 Jun 2008
Posts: 95
Concentration: Finance, Strategy
Schools: Chicago (Booth)  Class of 2014

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
21 Mar 2012, 09:56
Bunuel: Good approach!
_________________
__________________________________________ Giving kudos is the easiest way to thank someone
Nothing can stop the man with the right mental attitude from achieving his goal; nothing on earth can help the man with the wrong mental attitude.



Manager
Joined: 07 Dec 2011
Posts: 86
Location: India

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
23 Mar 2012, 03:36
nice approach Bunuel. It shortens the long process and makes it less error prone.



Manager
Joined: 30 May 2008
Posts: 53

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
15 Apr 2012, 18:43
Bunuel wrote: TomB wrote: If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?
A. Three B. Four C. Five D. Six E. Nine
bunnel , can you please explain this problem Given: \(t=\frac{1}{2^9*5^3}\). Multiply by \(\frac{5^6}{5^6}\) > \(t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625\). Hence \(t\) will have 4 zerose between the decimal point and the fist nonzero digit. Answer: B. Or another way \(t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}\). Now, \(\frac{1}{64,000}\) is greater than \(\frac{1}{100,000}=0.00001\) and less than \(\frac{1}{10,000}=0.0001\), so \(\frac{1}{64,000}\) is something like \(0.0000xxxx\). Answer: B. Can someone please explain how is multiplying 5^6 to the denominator (2^9 * 5^3) get 10^9?



Manager
Status: I will not stop until i realise my goal which is my dream too
Joined: 25 Feb 2010
Posts: 194

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
15 Apr 2012, 20:00
Bunuel wrote: TomB wrote: If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?
A. Three B. Four C. Five D. Six E. Nine
bunnel , can you please explain this problem Given: \(t=\frac{1}{2^9*5^3}\). Multiply by \(\frac{5^6}{5^6}\) > \(t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625\). Hence \(t\) will have 4 zerose between the decimal point and the fist nonzero digit. Answer: B. Or another way \(t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}\). Now, \(\frac{1}{64,000}\) is greater than \(\frac{1}{100,000}=0.00001\) and less than \(\frac{1}{10,000}=0.0001\), so \(\frac{1}{64,000}\) is something like \(0.0000xxxx\). Answer: B. 1st method is really awasome to follow...thanks Bunuel
_________________
Regards, Harsha
Note: Give me kudos if my approach is right , else help me understand where i am missing.. I want to bell the GMAT Cat
Satyameva Jayate  Truth alone triumphs



Intern
Joined: 19 Aug 2011
Posts: 22
Concentration: Finance, Entrepreneurship

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
16 Apr 2012, 05:14
Wow Bunuel, that was really good!



Intern
Joined: 16 Mar 2012
Posts: 32

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
29 Apr 2012, 09:34
Please I would like to know why you multiplied by 5^6. and I did not understand your second approach.



Math Expert
Joined: 02 Sep 2009
Posts: 51307

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
29 Apr 2012, 12:08



Intern
Joined: 02 Nov 2009
Posts: 39
Location: India
Concentration: General Management, Technology
GMAT Date: 04212013
GPA: 4
WE: Information Technology (Internet and New Media)

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
20 Oct 2012, 01:25
t= 1 / (2^9 * 5^3) or t=1/(2^3*5^3)*2^6 t=1/(10^3)*64 1/64 will be 0.01 and shifting the decimal point by three places to account for 1/10^3.. we get 4 zeros followed by 1.. Ans:B)
_________________
KPV



Manager
Joined: 27 Jul 2010
Posts: 157
Location: Prague
Schools: University of Economics Prague

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
20 Oct 2012, 01:58
With a question like this always try to convert the numbers to 10^(x) times something so that you can see the shift of the decimal point. As stated above, the answer is B.
_________________
You want somethin', go get it. Period!



Intern
Joined: 02 Sep 2012
Posts: 3

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
07 Jan 2013, 20:58
Hi, I still dont understand why we have to multiply by 5^6/5^6 i understand that this equals one but what is the general rule for this? how did you know to pick 5^6? Thanks Bunuel wrote: TomB wrote: If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?
A. Three B. Four C. Five D. Six E. Nine
bunnel , can you please explain this problem Given: \(t=\frac{1}{2^9*5^3}\). Multiply by \(\frac{5^6}{5^6}\) > \(t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625\). Hence \(t\) will have 4 zerose between the decimal point and the fist nonzero digit. Answer: B. Or another way \(t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}\). Now, \(\frac{1}{64,000}\) is greater than \(\frac{1}{100,000}=0.00001\) and less than \(\frac{1}{10,000}=0.0001\), so \(\frac{1}{64,000}\) is something like \(0.0000xxxx\). Answer: B.



Math Expert
Joined: 02 Sep 2009
Posts: 51307

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
08 Jan 2013, 02:16
shahir16 wrote: Hi, I still dont understand why we have to multiply by 5^6/5^6 i understand that this equals one but what is the general rule for this? how did you know to pick 5^6? Thanks Bunuel wrote: TomB wrote: If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?
A. Three B. Four C. Five D. Six E. Nine
bunnel , can you please explain this problem Given: \(t=\frac{1}{2^9*5^3}\). Multiply by \(\frac{5^6}{5^6}\) > \(t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625\). Hence \(t\) will have 4 zerose between the decimal point and the fist nonzero digit. Answer: B. Or another way \(t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}\). Now, \(\frac{1}{64,000}\) is greater than \(\frac{1}{100,000}=0.00001\) and less than \(\frac{1}{10,000}=0.0001\), so \(\frac{1}{64,000}\) is something like \(0.0000xxxx\). Answer: B. Welcome to GMAT Club shahir16. We want the denominator of the fraction to be written as some power of 10. We need that in order to transform the fraction into decimal easily. Now, the denominator = 2^9 * 5^3, hence we need to multiply it by 5^6 to get 10^9. Hope it's clear.
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics



Intern
Joined: 02 Sep 2012
Posts: 3

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
08 Jan 2013, 05:49
Can you please show me stepbystep how to convert 2^9 * 5^3 to a power of 10? I am unclear on the concept of converting an expression with exponents to a power of 10. I appreciate your help
Answer: B.[/quote][/quote]
Welcome to GMAT Club shahir16.
We want the denominator of the fraction to be written as some power of 10. We need that in order to transform the fraction into decimal easily.
Now, the denominator = 2^9 * 5^3, hence we need to multiply it by 5^6 to get 10^9.
Hope it's clear.[/quote]



Math Expert
Joined: 02 Sep 2009
Posts: 51307

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
08 Jan 2013, 09:15



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1825
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
23 Jun 2014, 01:59
\(\frac{1}{2^9 5^3}\) \(= \frac{5^6}{2^9 5^3 5^6}\) \(= \frac{125^2}{10^9}\) Count the numbers in numerator as equivalent to zero's in denominator \(= \frac{15625}{100000 . 10^4}\) \(10^4\) remains in denominator Answer = 4
_________________
Kindly press "+1 Kudos" to appreciate



Manager
Joined: 07 Apr 2014
Posts: 111

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
11 Sep 2014, 10:35
TomB wrote: If t = 1/(2^9*5^3) is expressed as a terminating decimal, how many zeros will t have between the decimal point and the fist nonzero digit to the right of the decimal point?
A. Three B. Four C. Five D. Six E. Nine t = 1/(2^9*5^3) 2^9 = 8^3 8^3 *5^3 = 40^3 1/64000 = there will be at least 3 zeros 1/64=0.0something ,,, adding another 3 zeros then 4 zeros



Manager
Joined: 23 Jan 2012
Posts: 60

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
11 Sep 2014, 17:37
Bunuel wrote: TomB wrote: If t = (1) / (2^9 * 5^3) is expressed as a terminating decimal, how many zeros will it have between the decimal point and the fist nonzero digit to the right of the decimal point?
A. Three B. Four C. Five D. Six E. Nine
bunnel , can you please explain this problem Given: \(t=\frac{1}{2^9*5^3}\). Multiply by \(\frac{5^6}{5^6}\) > \(t=\frac{5^6}{(2^9*5^3)*5^6}=\frac{25*625}{10^9}=\frac{15625}{10^9}=0.000015625\). Hence \(t\) will have 4 zerose between the decimal point and the fist nonzero digit. Answer: B. Or another way \(t=\frac{1}{2^9*5^3}=\frac{1}{(2^3*5^3)*2^6}=\frac{1}{10^3*64}=\frac{1}{64000}\). Now, \(\frac{1}{64,000}\) is greater than \(\frac{1}{100,000}=0.00001\) and less than \(\frac{1}{10,000}=0.0001\), so \(\frac{1}{64,000}\) is something like \(0.0000xxxx\). Answer: B. Awesome approach Bunuel...



Manager
Status: PLAY HARD OR GO HOME
Joined: 25 Feb 2014
Posts: 148
Location: India
Concentration: General Management, Finance
GPA: 3.1

Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho
[#permalink]
Show Tags
18 Sep 2014, 09:41
I used a slightly different method.. 1/2^9*5^3= 1/10^3*2^6 ....then,1/64=0.01 (dont need to calculate further since we have a non zero digit)....Now, 0.01/10^3 =0.00001 (shifting 3 decimals aside) Hence,4 zeros..
_________________
ITS NOT OVER , UNTIL I WIN ! I CAN, AND I WILL .PERIOD.




Re: If t = 1/(2^9*5^3) is expressed as a terminating decimal, ho &nbs
[#permalink]
18 Sep 2014, 09:41



Go to page
1 2
Next
[ 38 posts ]



